A crate slides off the back of a flatbed truck that accelerated forward from rest. If the bed of the truck is frictionless, the
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Answer:
the statement is False = cos θ
Explanation:
Let's analyze this problem, the ball and the receiver leave the same point and we want to know if at the same moment they reach the same point, for this we must have both the ball and the receiver travel the same distance.
Let's start by finding the time it takes for the ball to reach the ground
y = t - ½ g t²
when it reaches the ground its height is y = 0
0 = vo sin θ - ½ g t²
0 = t (vo sin θ - ½ g t)
The results are
t = 0 exit point
t = 2 v₀ sin θ/g arrival point
at this point the ball traveled
= v₀ₓ t
x_{ball} = v₀ cos θ 2v₀ sin θ / g
x_{ball}= 2 v₀² cos θ sin θ/ g
Now let's find that distantica traveled the receiver in time
= v₀ t
x_{rec} = v₀ (2 v₀ sin θ / g)
x_{rec} = 2 v₀² sin θ / g
without dividing this into two distances
= cos θ
therefore the distances are not equal to the ball as long as behind the receiver
Therefore the statement is False
Answer:
G.P.E = 5.292 Joules
Explanation:
Given the following data;
Mass = 0.6 kg
Height = 0.9 m
To find the gravitational potential energy;
Gravitational potential energy (GPE): it is an energy possessed by an object or body due to its position above the earth.
Mathematically, potential energy is given by the formula;
Where,
G.P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
But we know that acceleration due to gravity is equal to 9.8m/s²
G.P.E = 0.6*9.8*0.9
G.P.E = 5.292 Joules