The maximum diffraction order seen is 3.
<h3>What is the maximum diffraction order seen?</h3>
We know that the maximum angle of diffraction Q_m of the furthest bright fringe < Q = 90 degrees.
Here we need to compute the nth bright fringe for which is approximated to 90 degrees.
The angle of nth bright fringe is given by;
sin(Q_m) = n(λ)N
Approximating Q_m ≈ 90 degrees.
sin (90) = nλN
n = sin (90) / (λN)
n = 1 / ((580 x 10⁻⁶)500)
n = 3.5 orders
Since, we knew that Q_m < 90 degrees, we will choose n = 3 as the maximum number of orders.
Thus, the maximum diffraction order seen is 3.
Learn more about maximum diffraction here: brainly.com/question/14703089
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