Answer:
They are able to perform all necessary functions within one cell.
Explanation:
Answer:
haggis is the best place for a new dog and what's going to happen with the
Answer:
7.14 × 10^(-58) m
Explanation:
We are given;
Energy; E = 2.78 x 10^(32) J
Formula to find this energy is;
E = hc/λ
Where;
E is energy
h is Planck's constant with a constant value of 6.62 × 10^(-34) J/s
c is speed of light with a constant value of 3 × 10^(8) m/s
λ is wavelength
Making λ the subject, we have;
λ = hc/E
λ = (6.62 × 10^(-34) × 3 × 10^(8))/(2.78 x 10^(32))
λ = 7.14 × 10^(-58) m
Answer:
Cr₂S₃
Explanation:
From the question given above, the following data were obtained:
Mass of chromium (Cr) = 0.67 g
Mass of chromium sulfide = 1.2888 g
Empirical formula =?
Next, we shall determine the mass of sulphur (S) in the compound. This can be obtained as follow:
Mass of chromium (Cr) = 0.67 g
Mass of chromium sulfide = 1.2888 g
Mass of sulphur (S) =?
Mass of S = (Mass of chromium sulfide) – (Mass of Cr)
Mass of S = 1.2888 – 0.67
Mass of S = 0.6188 g
Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:
Mass of Cr = 0.67 g
Mass of S = 0.6188 g
Divide by their molar mass
Cr = 0.67 / 52 = 0.013
S = 0.6188 / 32 = 0.019
Divide by the smallest
Cr = 0.013 / 0.013 = 1
S = 0.019 / 0.013 = 1.46
Multiply by 2 to express in whole number
Cr = 1 × 2 = 2
S = 1.46 × 2 = 3
Therefore, the empirical formula of the compound is Cr₂S₃