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Cloud [144]
3 years ago
9

Classify the following reaction:2h2o 2h2 o2

Chemistry
2 answers:
lord [1]3 years ago
5 0
The classified form of the following reaction should looke like that :2 H2O (l) 2 H2(g) + O2(g). WHat about the name of such reaction, I am pretty sure that it is called <span>decomposition. I bet you have the same in the option list, but next time check it carefully.</span>
Delicious77 [7]3 years ago
3 0

Explanation:

When a substance or compound dissociates into two or more new compounds then this type of chemical reaction is known as decomposition reaction.

For example, 2H_{2}O \rightarrow 2H_{2} + O_{2}

Here, water dissociates into hydrogen and oxygen molecules.

Thus, we can conclude that the given reaction is a decomposition reaction.

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They are able to perform all necessary functions within one cell.

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Which chemical equation correctly represents the synthesis of calcium sulfite from calcium oxide and sulfur dioxide ?
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What is one of the names for a column in the periodic table?
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A photon has an energy of 2.78 x 1032 J. What is its wavelength?
8090 [49]

Answer:

7.14 × 10^(-58) m

Explanation:

We are given;

Energy; E = 2.78 x 10^(32) J

Formula to find this energy is;

E = hc/λ

Where;

E is energy

h is Planck's constant with a constant value of 6.62 × 10^(-34) J/s

c is speed of light with a constant value of 3 × 10^(8) m/s

λ is wavelength

Making λ the subject, we have;

λ = hc/E

λ = (6.62 × 10^(-34) × 3 × 10^(8))/(2.78 x 10^(32))

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3 0
3 years ago
A 0.67 gram sample of chromium is reacted with sulfur. The resulting chromium sulfide has a mass of 1.2888 grams. What is the em
spin [16.1K]

Answer:

Cr₂S₃

Explanation:

From the question given above, the following data were obtained:

Mass of chromium (Cr) = 0.67 g

Mass of chromium sulfide = 1.2888 g

Empirical formula =?

Next, we shall determine the mass of sulphur (S) in the compound. This can be obtained as follow:

Mass of chromium (Cr) = 0.67 g

Mass of chromium sulfide = 1.2888 g

Mass of sulphur (S) =?

Mass of S = (Mass of chromium sulfide) – (Mass of Cr)

Mass of S = 1.2888 – 0.67

Mass of S = 0.6188 g

Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:

Mass of Cr = 0.67 g

Mass of S = 0.6188 g

Divide by their molar mass

Cr = 0.67 / 52 = 0.013

S = 0.6188 / 32 = 0.019

Divide by the smallest

Cr = 0.013 / 0.013 = 1

S = 0.019 / 0.013 = 1.46

Multiply by 2 to express in whole number

Cr = 1 × 2 = 2

S = 1.46 × 2 = 3

Therefore, the empirical formula of the compound is Cr₂S₃

5 0
3 years ago
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