Answer:bromine , neon , helium , argon , lithium , beryllium
Explanation:
Answer:
44.28 grams.
Explanation:
Let us write the balanced reaction:

As per balanced equation, six moles of fluorine gas will give four moles of PF₃.
The mass of PF₃ required = 120 g
The molar mass of PF₃ = 88g/mol
Moles of PF₃ required =
The moles of fluorine gas required = 
the mass of fluorine gas required = moles X molar mass = 0.91x38 = 34.58g
Now this much mass will be required if the reaction is of 100% yield
But as given that the yield of reaction is only 78.1%
The mass of fluorine required = 
Answer:
Balanced chemical equation:
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂
Explanation:
Chemical equation:
Al + H₂SO₄ → Al₂(SO₄)₃ + H₂
Balanced chemical equation:
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂
Steps:
Let balance the SO₄ first.
Al + 3H₂SO₄ → Al₂(SO₄)₃ + H₂
There are three H₂ on left so put the coefficient three on right too.
Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂
Two Al on right and one on left so we will put the coefficient two on left.
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂
All atoms are correctly balanced.
NH3, usually it is called ammonium.