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adell [148]
3 years ago
11

X- 0,1,2,3 Y- 3,4,11,18. Which linear equatio represents the data given in the table? A) y = 3x + 7 B) y = 7x + 3 C) y = 3x - 7

D) y = 7x - 3
Mathematics
1 answer:
devlian [24]3 years ago
5 0

Answer:the answer is A

Step-by-step explanation:

I know because i took the quiz and got it right

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What does the 75th term look like of 6,9,12
leva [86]

Answer:

228

Step-by-step explanation:

We are adding 3 each time so general rule is

Tn= 3n + 3

Therefore

T= 3(75)+3

= 228

3 0
3 years ago
Read 2 more answers
Please need help for question number 26
kherson [118]

(8,12)(14,3)


Use midpoint formula


(X1+x2/2, y1+y2/2)


Substitute with your points


(8+14/2, 12+3/2)


Solve each


(22/2,15/2)


Cancel common factor 2


(2×(4+7)/2(1),15/2)


Simplify

(4+7/1,15/2)


This is your midpoint

(11, 15/2)




3 0
3 years ago
An=an-1+6an-2 <br> n&gt;2 a0=3 a1=6
Svetach [21]
\begin{cases}a_0=3\\a_1=6\\a_n=a_{n-1}+6a_{n-2}&\text{for }n>2\end{cases}

Let the generating function for a_n be

A(x)=\displaystyle\sum_{n\ge0}a_nx^n

Multiplying both sides by x^{n-2}

a_nx^{n-2}=a_{n-1}x^{n-2}+6a_{n-2}x^{n-2}

Summing both sides over the non-negative integers greater than or equal to 2 gives

\displaystyle\sum_{n\ge2}a_nx^{n-2}=\sum_{n\ge2}a_{n-1}x^{n-2}+6\sum_{n\ge2}a_{n-2}x^{n-2}
\displaystyle\frac1{x^2}\sum_{n\ge2}a_nx^n=\frac1x\sum_{n\ge1}a_nx^n+6\sum_{n\ge0}a_nx^n
\displaystyle\frac1{x^2}\left(\sum_{n\ge0}a_nx^n-a_0-a_1x\right)=\frac1x\left(\sum_{n\ge0}a_nx^n-a_0\right)+6\sum_{n\ge0}a_nx^n
\displaystyle\frac1{x^2}\left(A(x)-3-6x\right)=\frac1x\left(A(x)-3\right)+6A(x)
A(x)=\dfrac{3x+3}{1-x-6x^2}
A(x)=\dfrac3{5(1+2x)}+\dfrac{12}{5(1-3x)}

For |x|, the two series converge to

\displaystyle A(x)=\frac35\sum_{n\ge0}(-2x)^n+\frac{12}5\sum_{n\ge0}(3x)^n
\implies A(x)=\displaystyle\sum_{n\ge0}\dfrac{3(-2)^n+12(3)^n}5x^n
a_n=\dfrac{3(-2)^n+12(3)^n}5=\dfrac{3(-2)^n+4(3)^{n+1}}5
5 0
3 years ago
Can someone just explain pre-image and image to me? ​
user100 [1]

Answer: in doing transformations, the pre-image is the image you start with. The task is to move the pre-image so that it is contiguous with the (target) image. This is typically done by translation, rotation or reflection or a combination of those moves.

Hope that helps

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Cruz's Frame shop makes. a mat by cutting out the inside of a rectangular mat board. Find the length and width of the original m
max2010maxim [7]

Answer:

length = 23 inches; width = 18 inches.

Step-by-step explanation:

Length and width are found from their expressions after solving for x. The value of x can be found from ...

... overall area - cutout area = 148 . . . . . . square inches

... (2x -1)(x +6) - (2x -5)(x +2) = 148 . . . . . substitute length and width expressions. Each area is the product of length and width.

... 2x² +11x -6 -(2x² -x -10) = 148 . . . . . . . multiply binomials

... 12x +4 = 148 . . . . collect terms

... 12x = 144 . . . . . . . subtract 4

... x = 12 . . . . . . . . . . divide by 12

Then the overall length is ...

... 2x -1 = 2·12 -1 = 23 . . . inches

and the overall width is ...

... x +6 = 12 +6 = 18 . . . inches

The overall dimensions of the original mat are 23 inches by 18 inches.

4 0
3 years ago
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