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zaharov [31]
3 years ago
13

If 2 is equal to 127°, what is the measure of 1?

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0
If the measure of angle 2 is 127, then the measure of angle 1 must equal 53 because angle 2 and angle 1 are linear angles. Linear angles are angles that are supplementary, or whose measures add up to 180. To find the measure of angle 1 you would need to subtract 127 from 180.
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In the 30-60-90 triangle below, side s has a length of _ and side q has a length of _.
gregori [183]

Answer: F

Step-by-step explanation:

For a 30-60-90 triangle, we know that the hypotenuse is 2x. Since we know the hypotenuse is 10, we can solve for x.

2x=10

x=5

Now that we know x is 5, we can use this to solve for s and q. The side across from 30° is just x. Since we know x, s is 5.

The side across from 60° is x√3. Since we know what x is, we can just plug in. q is 5√3.

4 0
3 years ago
Armando also thinks the first question should be worth $5. However, he thinks a contestant's winnings should double with each su
lesya [120]

p =  5+ {n}^{2}
6 0
3 years ago
The length of an object's shadow varies directly with It's heigt. If a can is 13 cm tall casts a shadow that is 7.5 cm long, a b
svetoff [14.1K]
X = Can/Bottle height, y = Shadow length
x = 13 cm, y = 7.5 cm
x = 2.5 cm, y = 14.2 cm
I'm assuming your question is asking for an equation to model this. Since there are only two data points the only equation that can be made is linear
y = mx + c
m = (y2 - y1)/(x2 - x1) <- Let 14.2 be y2, and 2.5 be x2 (it is important)
m = (14.2 - 7.5)/(2.5 - 13)
m = 6.7/-10.5
m = -0.638
y = -0.638x + c
To find c we can sub any one of the two coordinates, 
i'm choosing (2.5,14.2)
14.2 = -0.638(2.5) + c
14.2 = -1.595 + c
14.2 + 1.595 = c
15.795 = c
So the final equation is y = -0.638x + 15.795
6 0
3 years ago
Phillip wrote an integer that is less than -2 and greater than -3.5. Which integer did he write?
yan [13]
He could have wrote -2.5 or -3.
3 0
3 years ago
WILL MARK BRAINLIEST ASAP!!
7nadin3 [17]

\dfrac{x^2+ax-4}{x+2}+\dfrac{x+b}{x+2}=\dfrac{x^2+ax-4+x+b}{x+2}=\dfrac{x^2+(a+1)x+(b-4)}{x+2}\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=x+1\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=\dfrac{(x+1)(x+2)}{x+2}\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=\dfrac{(x)(x)+(x)(2)+(1)(x)+(1)(2)}{x+2}\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=\dfrac{x^2+2x+x+2}{x+2}\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=\dfrac{x^2+3x+2}{x+2}\iff a+1=3\ \wedge\ b-4=2\\\\\boxed{a=2\ \wedge\ b=6}

3 0
3 years ago
Read 2 more answers
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