Question

A plane electromagnetic wave traveling in the positive direction of an x axis in vacuum has components Ex = Ey = 0 and Ez = (5.2 V/m) cos[(π × 1015 s-1)(t - x/c)].(a) What is the amplitude of the magnetic field component? (b) Parallel to which axis does the magnetic field oscillate? (c) When the electric field component is in the positive direction of the z axis at a certain point P, what is the direction of the magnetic field component there? Assume that the speed of light is 2.998*108 m/s.

Answer 1

Answer:

Explanation:

Ez = (5.2 V/m)

Magnitude of electric field = 5.2 V/m

Magnitude of magnetic field be B then

Magnitude of electric field  / Magnitude of magnetic field = c , c is velocity of light

5.2 / B = 2.998 x 10⁸

B = 5.2 / 2.998 x 10⁻⁸

= 1.73 x 10⁻⁸ T.

b ) E X B = direction of velocity of light , E is electric vector , B is magnetic V.

E is along z - axis , velocity is along x -axis  , then magnetic field must be in   - Y direction.

c ) E and B  are in phase so when E is in positive z axis , directio of magnetic field must be in  -  y direction.