Answer:
hi
Explanation:
hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii
Answer:
average speed and velocity are 0.5m/s (squared)
Answer:
Option E is correct.
There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.
Explanation:
Normally, ignoring air resistance, for projectile motion, the range (horizontal distance teavelled) of the motion is given as
R = (u² sin 2θ)/g
where
u = initial velocity of the projectile = 20 m/s
θ = angle above the horizontal at which the projectile was launched = 30°
g = acceleration due to gravity = 9.8 m/s²
R = (30² sin 60°) ÷ 9.8
R = 78.53 m
So, Normally, the stone should travel a horizontal distance of 78.53 m. So, travelling a horizontal distance of 32 m (less than half of what the range should be without air resistance) means that, the motion of the stone was impeded, hence, option E is correct.
There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.
Hope this Helps!!!
Answer:
Magnitude |VB| = 0.32 m/s
and
Direction is to the left
Explanation:
given data
glider A mass = 0.125 kg
glider B mass = 0.500 kg
glider A move = 0.960 m to the left
solution
we use here Conservation of momentum that is
M1 × U1 + M2 × U2 =M1 × V1 + M2 × V2 ........................1
put here value and we get
0.125 × 0 + 0.500 × 0 = 0.125 × 0.960 + 0.375 × VB
VB = −0.32 m/s
Magnitude |VB| = 0.32 m/s
and
Direction is to the left
