Question

A potter's wheel moves uniformly from rest to an angular speed of 0.16 rev/s in 31 s. (a) Find its angular acceleration in radians per second per second. rad/s2 (b) Would doubling the angular acceleration during the given period have doubled final angular speed?

Answer 1

Answer:

a) 0.0324 rad/s²

b) 2.01 rad/s , the final angular speed gets doubled

Explanation:

w₀ = initial angular speed = 0 rad/s

w = final angular speed = 0.16 rev/s = 0.16 (6.28) = 1.005 rad/s

t = time interval = 31 s

α = angular acceleration

final angular speed is given as

w = w₀ + α  t

1.005 = 0 + α (31)

α = 0.0324 rad/s²

b)

After the acceleration is doubled

α' = 2 α = 2 (0.0324) = 0.0648 rad/s²

w' = final angular speed

w'₀ = initial angular speed = 0 rad/s

final angular speed is given as

w = w₀ + α  t

w = 0 + (0.0648) (31)

w = 2.01 rad/s

yes the final angular speed gets doubled