A lightbulb is rated by the power that it dissipates when connected to a given voltage. For a lightbulb connected to 120 V house
1 answer:
Answer:
Increase, increase
Explanation:
For a light bulb, voltage, resistance and current follows the Ohm's law:
where
V is the voltage
R is the resistance
I is the current
In this problem, the voltage is fixed: V=120 V. We can rewrite the equation as
(1)
we see that the current is inversely proportional to the resistance: so, if we decrease the resistance of the filament, the current will increase.
Moreover, the power dissipated by the bulb is
which can be rewritten using (1) as
We see that the power dissipated is inversely proportional to the resistance: therefore, if we decrease the resistance of the filament, the power dissipated will increase.
You might be interested in
The mass of ball a is twice the mass of ball b:
This means that the initial potential energy of ball a (
) is twice the potential energy of ball b (
):
When the two balls reach the ground, the potential energy of each ball has converted into kinetic energy (since now their altitude is h=0), because the total mechanical energy of each ball must be conserved. Therefore:
and so the kinetic energy of ball a must be twice the kinetic energy of ball b:
This means that the initial potential energy of ball a (
When the two balls reach the ground, the potential energy of each ball has converted into kinetic energy (since now their altitude is h=0), because the total mechanical energy of each ball must be conserved. Therefore:
and so the kinetic energy of ball a must be twice the kinetic energy of ball b:
Answer:
c. Vessel side holes
Explanation:
- The "Poiseuille formula" which is given by
describes the volumetric flow rate (
) through tubular sections.
- Here,
represent the injection pressure difference, the length of the section, the radius of the section and the viscosity index of the fluid that flows through the section respectively.
- With this, one can confirm that all the factors except the vessel side holes affect the flow rate.
- Side holes, however, are a factor that could give a measure of how much volume would flow to a particular location. In such a situation the flow rate remains unchanged and one location would receive a lower volume (not the whole) as some volume would spill out at the side holes.
#SPJ4