A student lifts 100 N of books 1 m to his shoulder. He walks forward
1 answer:
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Answer:
The minimum value is
Explanation:
From the question we are given that
The voltage is
The internal resistance is
The objective of this solution is to obtain the minimum value of the voltmeter resistance for which the voltmeter reading is within 1.0% of the emf of the battery
What is means is that we need to obtain voltmeter resistance such that
V = (100% -1%) of E
Where E is the e.m.f of the battery and V is the voltmeter reading
i.e V = 99% of E = 0.99 E = 7.425
Generally
E = V + ir
where ir is the internal potential difference of the voltmeter and
V is the voltmeter reading
Making i the subject of the formula above
Now the current is constant through out the circuit so,
Where is the value of voltmeter resistance
Hence
Answer:
0.00384 kg/m
Explanation:
The fundamental frequency of string waves is given by
For some tension (F) and length (L)
Fundamental frequency of G string
Fundamental frequency of E string
Linear mass density of E string is
So,
The linear density of the G string is 0.00384 kg/m
391.12 * mass is required for activity of 315 ci
The activity of the radioactive substance is the number of disintegrations taking place in a radioactive sample.
Isotopes are the members of an element having the same number of protons but the different number of neutrons.
the activity of the radioactive sample is given as:
A = λ * N
where λ is the decay constant and N is the number of disintegrations.
activity is given as 315 ci
A = 315 * 3.7 *
= 1165.5 * Bq
λ = 0.693 /
= 0.693 / 2.69 * 24 * 3600
= 2.98 * t^-1
Therefore, N = A / λ
= 1165.5 * / 2.98 *
N = 391.12 *
391.12 * mass is required for activity of 315 ci
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