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3 years ago

A student lifts 100 N of books 1 m to his shoulder. He walks forward

Physics

1 answer:

Delvig [45]3 years ago

7 0

Hope this will help u.....:)

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Discuss the relationship between amperage, voltage, and power.

Stells [14]

Electrical power, in watts = (voltage, in volts) x (current, in Amperes)

5 0

3 years ago

WILL UPVOTE!!!Physics help please!!

liubo4ka [24]

Speed v = initial speed u + acceleration a x time t
v=u+at = 2 + 4*3 = 14 m/s

8 0

3 years ago

What's is the kinetic energy of a .235-kg baseball thrown at 50.0m/s

san4es73 [151]

Answer:

34.51

Explanation:

k=1/2mv² is the kenetic energy equation to fill is in

k=[1/2(0.235)×50]²

6 0

3 years ago

A biker first accelerates from 0.0 m/s to 6.0 m/s in 6 s, then continues at this speed for 5 s. What is the total distance trave

Svetradugi [14.3K]

Answer:

48m

Explanation:

Given the following data;

Initial velocity = 0m/s

Final velocity = 6m/s

Time, t = 6 secs

Time, T2 = 5 secs

Mathematically, acceleration is given by the equation;

$Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}$

Substituting into the equation;

$a = \frac{6 - 0}{6}$

$a = \frac{6}{6}$

Acceleration, a = 1m/s²

To find the distance covered in the first phase;

Solving for distance, we would use the second equation of motion;

$S = ut + \frac {1}{2}at^{2}$

Substituting the values into the equation;

$S = 0(6) + \frac {1}{2}*1*(6)^{2}$

$S = 0 + \frac {1}{2}*1*36$

$S = 0.5 *36$

Distance, S1 = 18m

For the second phase, time T2 = 5 secs;

Mathematically, speed is given by the equation;

$Speed = \frac{distance}{time}$

Making distance the subject of formula, we have;

$Distance, S = speed * time$

Substituting into the above equation;

$Distance, S = 6 * 5$

Distance, S2 = 30m

Total distance = S1 + S2 = 18m + 30m = 48m

Total distance = 48m

Therefore, the total distance traveled by the biker is 48m.

4 0

3 years ago

A box of mass 50 kg is pushed hard enough to set it in motion across a flat surface. Then a 99-N pushing force is needed to keep

vitfil [10]

Answer:

0.20

Explanation:

The box is moving at constant velocity, which means that its acceleration is zero; so, the net force acting on the box is zero as well.

There are two forces acting in the horizontal direction:

- The pushing force: F = 99 N, forward

- The frictional force: $F_f=\mu mg$ , backward, with

$\mu$ coefficient of kinetic friction

m = 50 kg mass of the box

g = 9.8 m/s^2 gravitational acceleration

The net force must be zero, so we have

$F-F_f = 0$

which we can solve to find the coefficient of kinetic friction:

$F-\mu mg=0\\\mu = \frac{F}{mg}=\frac{99 N}{(50 kg)(9.8 m/s^2)}=0.20$

7 0

3 years ago