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frosja888 [35]
3 years ago
10

Which one is the graph?

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
7 0

Answer:

f(1) = √(4*1) = √4 = 2

The point (1, 2) is only on the third graph.


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Help please due today!!
julia-pushkina [17]
In this image, the two angles (equations) form a right angle, which is 90°. You combine these equations: 4y-7+3y-1. When you combine like terms, you get 7y-8. You set this equal to 90°. 7y-8=90. Solve for y, and you get y=12.
8 0
3 years ago
Two patrol boats leave Cape May at the same time, the same speed, but on different bearings. One has bearing 41°45
VMariaS [17]

Based on the information given, the computation shows that the distance between them is 2.47 miles.

<h3>Solving the distance.</h3>

Since one has bearing 41°45', this will be: = 41° + (45/60) = 41° + 0.75 = 41.75°.

The other has bearing 59°13'. This will be:

= 59° + (13/60) = 59° + 0.22 = 59.22°.

The difference of the angles will be:

= 59.22° - 41.75°

= 17.47°

Let the distance between them be represented by c. Therefore, we'll use cosine law to solve the question. This will be:

c² = a² + b² - 2ab cos 17.47°

c² = 20² + 20² - (2 × 20 × 20 × 0.19)

c² = 6.07459

c = 2.47

Learn more about distance on:

brainly.com/question/2854969

8 0
2 years ago
Find the perimeter of the figure. Round your answer to the nearest hundredth. <br><br><br><br> in.
Vanyuwa [196]

Answer:

61.13

Step-by-step explanation:

2\pi(4) = 8\pi = 25.13

25.13 + 10 + 10 + 8 + 8 = 61.13

6 0
3 years ago
Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)
viktelen [127]
\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}

The first line segment can be parameterized by \mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle with 0\le t\le1. Denote this first segment by C_1. Then

\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt
=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt
=108

The second line segment (C_2) can be described by \mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle, again with 0\le t\le1. Then

\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt
=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt
=-\dfrac{229}3

Finally,

\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3
5 0
3 years ago
A customer is late paying their renewal registration fee. The renewal registration fee is $142.16 and the late fee is 63% of the
Andre45 [30]
$124.56 because if you have 63% you change it to a decimal so it is not .63 and you multiply it by 146.16 and then add the 35 you get 124.56
8 0
3 years ago
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