<em>The </em><em>value</em><em> </em><em>of</em><em> </em><em>u</em><em> </em><em>is</em><em> </em><em>-</em><em>3</em><em>4</em><em>3</em>
<em>pl</em><em>ease</em><em> see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em>
<em>Hope</em><em> </em><em>it</em><em> helps</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
Answer:

Step-by-step explanation:
We have been given that the rectangle has an area of
square meters and a length of
. We are asked to find the width of rectangle.
Since we know that area of a rectangle is width times length of the rectangle, so we can find width of our given rectangle by dividing given area by length of rectangle.



Upon substituting our given values in above formula we will get,


Using exponent rule for quotient
we will get,


Therefore, width of our given rectangle will be 9x meters.
All internal angles in a quadrilateral add to 360
so
x+110+110+70=360
x+290=360
minus 290 both sides
x=70 degrees
Area of the large semicircle





Area of the small semicircle





Area of the figure


The height of the container be so as to minimize cost will be 1.20. inches.
<h3>How to calculate the height?</h3>
The volume of the box will be:
= 2x × 3x × h
= 6x²h
Volume = 6x²h
12 = 6x²h
h = 2x²
The cost function will be:
C = 2.60(2)(6x²) + 4.30(12x)h
C = 31.2x² + 51.6xh
Taking the derivative
62.4x + 51.6h
h = 1.20
Therefore, the height of the container be so as to minimize cost will be 1.20 inches.
Learn more about height on:
brainly.com/question/15557718
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