Answer:
d) 15.12 N
e) 15.12 N
Explanation:
Draw a free body diagram of the each block.
Block A has three forces on it: weight force mAg pulling down, normal force N pushing up, and tension force T pulling down.
Block B has two forces on it: weight force mBg pulling down, and tension force T pulling up.
Sum of forces on A in the y direction:
∑F = ma
T + N − mAg = mAa
N = mAa + mAg − T
N = mA (a + g) − T
Sum of forces on B in the y direction:
∑F = ma
T − mBg = mBa
T = mBa + mBg
T = mB (a + g)
Plug in values:
T = (1.80 kg) (-1.60 m/s² + 10 m/s²)
T = 15.12 N
N = (3.60 kg) (-1.60 m/s² + 10 m/s²) − 15.12 N
N = 15.12 N
So the answers to (d) and (e) are both 15.12 N.
