Answer: rp/re= me/mp= 544 * 10^-6.
Explanation: To calculate this problem we have to consider the circular movement by the electron and proton inside a magnetic field.
Then the dynamic equation for the circular movement is given by:
Fcentripetal= m*ω^2.r
q*v*B=m*ω^2.r
we write this for each particle then we have the following:
q*v*B=me* ω^2*re
q*v*B=mp* ω^2*rp
rp/re=me/mp=9.1*10^-31/1.67*10^-27=544*10^-6
11.46 meters
55 km/h = ? m/s
55 km/h × 1000 (meters per km) = 55,000 m/h
55,000 m/h ÷ 3,600 (seconds in an hour) = 15.28 m/s
15.28 m/s × 0.75 s = 11.46 m
Answer:
Multiply the x values with -1.
Explanation:
By multiplying the numbers by one, you are changing them to be the opposite of their original state.
You multiply the numbers that are in the x-value column because you are reflecting the image over the y-axis.
<em>Hope this helped and good luck!</em>
A por que chu papi es mui rico xisjsjsjsjajsjasjananansjsjsjsjs
Answer:
v = 0.0147 m / s
Explanation:
For this exercise let's use energy conservation
Starting point. Fully stretched spring
Em₀ = Ke = ½ k (x-x₀)²
Final point. Unstretched position
Emf = K = ½ m v²
Emo = Emf
½ k (x- x₀)² = ½ m v²
v = √m/k (x-x₀)
Let's calculate
v = √(0.022 / 0.5) (0.26-0.19)
v = 0.0147 m / s