Answer:
2 m.
Explanation:
From the question given, the following data were obtained:
Initial velocity (u) = 2 m/s
Initial time = 2 s
Final velocity (v) = 4 m/s
Final time (t) = 3 s
Next, we shall determine the change in velocity. This can be obtained as follow:
Initial velocity (u) = 2 m/s
Final velocity (v) = 4 m/s
Change in velocity (Δv) =?
Change in velocity (Δv) = v – u
Change in velocity (Δv) = 4 – 2
Change in velocity (Δv) = 2 m/s
Next, we shall determine the change in time. This can be obtained as follow:
Initial time (t1) = 2 s
Final time (t2) = 3 s
Change in time (Δt) =..?
Change in time (Δt) = t2 – t1
Change in time (Δt) = 3 – 2
Change in time (Δt) = 1 s
Finally, we shall determine the displacement (Δx) of the peacock as follow:
Velocity (Δv) = 2 m/s
Time ((Δt) = 1 s
Displacement (Δx) =?
Velocity = Displacement /Time
ΔV = Δx/Δt
2 = Δx /1
2 = Δx
Δx = 2 m
Therefore, the displacement of the peacock is 2 m
