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3 years ago

A peacock is flying around and its velocity

Physics

1 answer:

rodikova [14]3 years ago

4 0

Answer:

2 m.

Explanation:

From the question given, the following data were obtained:

Initial velocity (u) = 2 m/s

Initial time = 2 s

Final velocity (v) = 4 m/s

Final time (t) = 3 s

Next, we shall determine the change in velocity. This can be obtained as follow:

Initial velocity (u) = 2 m/s

Final velocity (v) = 4 m/s

Change in velocity (Δv) =?

Change in velocity (Δv) = v – u

Change in velocity (Δv) = 4 – 2

Change in velocity (Δv) = 2 m/s

Next, we shall determine the change in time. This can be obtained as follow:

Initial time (t1) = 2 s

Final time (t2) = 3 s

Change in time (Δt) =..?

Change in time (Δt) = t2 – t1

Change in time (Δt) = 3 – 2

Change in time (Δt) = 1 s

Finally, we shall determine the displacement (Δx) of the peacock as follow:

Velocity (Δv) = 2 m/s

Time ((Δt) = 1 s

Displacement (Δx) =?

Velocity = Displacement /Time

ΔV = Δx/Δt

2 = Δx /1

2 = Δx

Δx = 2 m

Therefore, the displacement of the peacock is 2 m

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