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liberstina [14]
3 years ago
10

A vertical scale on a spring balance reads from 0 to 200 \rm{N}. The scale has a length of 10.0 \rm{cm} from the 0 to 200 \rm{N}

reading. A fish hanging from the bottom of the spring oscillates vertically at a frequency of 2.05 \rm{Hz}.
Ignoring the mass of the spring, what is the mass m of the fish?
Physics
1 answer:
pav-90 [236]3 years ago
8 0

Answer:

m = 12.05 kg

Explanation:

Spring constant in K, N/m

K = 200/10* 100

K = 2000 N/m

Angular Frequency = sqrt (Spring constant / (Mass )

ω = 2 π f

ω =  2π* 2.05 Hz = 12.8805 rad/s

ω^2 = Spring constant / Mass

Mass= Spring constant / ω^2

ω^2 = 165.907 rad^2/s^2

m = 2000 (N/m)/165.907 (rad^2/s^2)

m = 12.05 kg

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I am the particle that is so small that scientists treat me as though I have no mass. Scientists also figure that I probably spe
tatyana61 [14]

Answer:

its electrons

Explanation:

only electrons stays outside the nucleus unlike protons and neutrons and it has little to no mass

8 0
3 years ago
You are an electrician installing the wiring in a new home. The homeowner desires that a ceiling fan with light kits be installe
In-s [12.5K]

Answer:

3 fans per 15 A circuit

Explanation:

From the question and the data given, the light load let fan would have been

(60 * 4)/120 = 240/120 = 2 A.

Next, we add the current of the fan motor to it, so,

2 A + 1.8 A = 3.8 A.

Since the devices are continuos duty and the circuit current must be limited to 80%, then the Breaker load max would be

0.8 * 15 A = 12 A.

Now, we can get the number if fans, which will be

12 A/ 3.8 A = 3.16 fans, or approximately, 3 fans per 15 A circuit.

8 0
3 years ago
NASA is giving serious consideration to the concept of solar sailing. A solar sailcraft uses a large, low- mass sail and the ene
RUDIKE [14]

Answer:

<em>d. The sail should be reflective because in this case the momentum transferred to the sail per unit area per unit time is larger than for absorbing sail, therefore the radiation pressure is larger for the reflective sail.</em>

<em></em>

Explanation:

Let us take the momentum of a photon unit as u

we know that the rate of change of momentum is proportional to the force exerted.

For a absorbing surface, the photon is absorbed, therefore the final momentum is zero. From this we can say that

F = (u - 0)/t = u/t

for a unit time, the force is proportional to the momentum of the wave due to its energy density. Therefore,

F = u

For a reflecting surface, the momentum of the wave strikes the sail and changes direction. Since we know that the speed of light does not change, then the force is proportional to

F = (u - (-u))/t = 2u/t

just as the we did above, it becomes

F = 2u.

From this we can see that the force for a reflective sail is twice of that for an absorbing sail, and we know that the pressure is proportional to the force for a given area. From these, we conclude that <em>the sail should be reflective because in this case the momentum transferred to the sail per unit area per unit time is larger than for absorbing sail, therefore the radiation pressure is larger for the reflective sail.</em>

<em></em>

3 0
3 years ago
A potential energy function is given by u(x)=(3.00n)xâ(1.00n/m2)x3. at what position or positions is the force equal to zero?
qwelly [4]

I believe the correct form of the energy function is:

u (x) = (3.00 N) x + (1.00 N / m^2) x^3

or in simpler terms without the units:

u (x) = 3 x + x^3

Since the highest degree is power of 3, therefore there are two roots or solutions of the equation.

 

Since we are to find for the positions x in which the force equal to zero, u (x) = 0, therefore:

3 x + x^3 = u (x)

3 x + x^3 = 0

Taking out x:

x (3 + x^2) = 0

So one of the factors is x = 0.

 

Finding for the other two factors, we divide the two sides by x and giving us:

x^2 + 3 = 0

x^2 = - 3

x = sqrt (- 3)

x = - 1.732 i, 1.732 i

 

The other two roots are imaginary therefore the force is only equal to zero when the position is also zero.

 

Answer:

x = 0

5 0
3 years ago
John rows his canoe due east across a river at 5.5 miles per hour. if the river is flowing south at 4 miles per hour, find john’
Juli2301 [7.4K]
This is the concept of trigonometry, the direction of the John will be given by:
tan theta=opposite/adjacent
suppose:
a=theta
opposite=4 mph
adjacent=5.5 mph
tan a=4/5.5
a=tan^-1(4/5.5)
a=36
therefore the boat canoe will be moving 36 degrees from East, his direction will be 126 degrees south east
5 0
3 years ago
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