All categories

2 years ago

Which best describe the kinetic energy of the particles in solids, liquids, and gases? Check all that apply.

Physics

2 answers:

AleksandrR [38]2 years ago

8 0

The Answers to this question are 1,3,5 on Edginuity

Mashcka [7]2 years ago

4 0

It should be answer 1

You might be interested in

What is the Sl unit of Newton ?............

kenny6666 [7]

Answer:

N is the SI unit of Newton

5 0

2 years ago

Read 2 more answers

NaOH + FeCl3* Na Cl + Fe 10H)3 balanced

zvonat [6]

3NaOH + FeCl3 → 3NaCl + Fe(OH)3

8 0

2 years ago

Holding onto a tow rope moving parallel to a frictionless ski slope, a 70.1 kg skier is pulled up the slope, which is at an angl

lara [203]

Answer:

given,

mass of the skier = 70.1 Kg

angle with horizontal, θ = 8.6°

magnitude of the force,F = ?

a) Applying newton's second law

$m g sin\theta - F_{rope} = ma$

velocity is constant, a = 0

$m g sin\theta - F_{rope} =0$

$F_{rope} = m g sin\theta$

$F_{rope} = 70.1\times 9.8\times sin 8.6^0$

$F_{rope}= 102.73\ N$

b) now, when acceleration, a = 0.135 m/s²

$F_{rope}-m g sin\theta = ma$

velocity is constant, a = 0.135 m/s₂

$F_{rope} = m g sin\theta+ma$

$F_{rope} = 70.1\times 9.8\times sin 8.6^0+70.1\times 0.135$

$F_{rope}= 112.19\ N$

7 0

3 years ago

A speaker vibrates at a frequency of 200 Hz. What is its period

Daniel [21]

Period, T = 1/ f.
f = frequency = 200 Hz.

Period T = 1/200 = 0.005 seconds.

8 0

2 years ago

f an arrow is shot upward on the moon with velocity of 35 m/s, its height (in meters) after t seconds is given by h(t)=35t−0.83t

inysia [295]

Answer:

The velocity of the arrow after 3 seconds is 30.02 m/s.

Explanation:

It is given that,

An arrow is shot upward on the moon with velocity of 35 m/s, its height after t seconds is given by the equation:

$h(t)=35t-0.83t^2$

We know that the rate of change of displacement is equal to the velocity of an object.

$v(t)=\dfrac{dh(t)}{dt}\\\\v(t)=\dfrac{d(35t-0.83t^2)}{dt}\\\\v(t)=35-1.66t$

Velocity of the arrow after 3 seconds will be :

$v(t)=35-1.66t\\\\v(t)=35-1.66(3)\\\\v(t)=30.02\ m/s$

So, the velocity of the arrow after 3 seconds is 30.02 m/s. Hence, this is the required solution.

7 0

2 years ago