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Murljashka [212]

3 years ago

12

Which choice lists the correct order of the coefficients of each substance in the following neutralization reaction when the equ

ation is balanced correctly? H2SO4 + LiOH → Li2SO4 + H2O.
-1,1,1,1
-2,1,2,1
-1,2,1,2
-1,2,1,1
which one of these options is it?

1 answer:

Gnoma [55]3 years ago

4 0

The third one you have listed

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Write the 1 g equivalents using the following prefixes: (a) mega−, (b) kilo−, (c) deci−, (d) centi−, (e) milli−, (f) micro−, (g)

dem82 [27]

<u>Explanation:</u>

Unit is defined as the quantity that is used as a standard for measurement.

S.I. unit of mass of kilograms. Other units in which mass of a substance can be measured are grams, milligrams, etc...

All these units are inter convertible.

<u>For a:</u> Mega-

The conversion factor used is:

$1g=10^{-6}Mg$

<u>For b:</u> kilo-

The conversion factor used is:

$1g=10^{-3}kg$

<u>For c:</u> deci-

The conversion factor used is:

$1g=10dg$

<u>For d:</u> centi-

The conversion factor used is:

$1g=10^{3}cg$

<u>For e:</u> milli-

The conversion factor used is:

$1g=10^3mg$

<u>For f:</u> micro-

The conversion factor used is:

$1g=10^6\mu g$

<u>For g:</u> nano-

The conversion factor used is:

$1g=10^9ng$

<u>For h:</u> pico-

The conversion factor used is:

$1g=10^{12}pg$

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The moon is 260,000 miles away. How many feet is it from earth?

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Answer:

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Explanation:

1 Mile = 5280 Feet

260,000 Miles = 5280 × 260,000 Feet

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Answer:

See detailed explanation.

Explanation:

Hello!

In this case, for the described chemical reaction, we can proceed as follows:

A) For the complete chemical reaction we note down every reacted and produced species as well as the proper balancing process:

$2NaBr(aq)+Cl_2(aq)\rightarrow 2NaCl(aq)+Br_2(g)$

In which gaseous bromine may give off.

B) The dissociated ionic equation requires the ionization of the aqueous species in ions, expect for chlorine which is not ionized:

$2Na^+(aq)+2Br^-(aq)+Cl_2(aq)\rightarrow 2Na^+(aq)+2Cl^-(aq)+Br_2(g)$

C) For the net ionic equation we cancel out the sodium ions as they are at both reactants and products:

$2Br^-(aq)+Cl_2(aq)\rightarrow +2Cl^-(aq)+Br_2(g)$

D) Based on C) we infer that the spectator ions here are the sodium ions.

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