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Gemiola [76]
3 years ago
12

Explain how one isotope of an element differs from another

Chemistry
1 answer:
algol133 years ago
5 0
One isotope differs from another in the number of neutrons they have.
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Chemical formula name for V2(SO2)3 (aq) explain why​
goldenfox [79]

This is the chemical doula for salt which is a polyatomic anion very prevalent in out daily lives e.g.

Salts, acid derivatives, and peroxides of sulfate are widely used in industry.

3 0
3 years ago
At which temperature would a can of soda be most fizzy when it is opened? 30°C 40°C 20°C 10°C
Helga [31]

The answer to your question is 40° because freezing temp for a liquid is 32°

4 0
2 years ago
Read 2 more answers
A sucrose solution is prepared to a final concentration of 0.250 M . Convert this value into terms of g/L, molality, and mass %.
MArishka [77]

Answer:

A. 85.6 g

= 0.0856 kg.

B. 0.00027 mol/g

= 0.27 mol/kg.

C. 8.39 %

Explanation:

Given:

Molar concentration = 0.25 M

Molar weight of sucrose = 342.296 g/mol

Density of solution = 1.02 g/mL

Mass of water = 934.4 g.

Density in g/l = 1.020 g/ml * 1000ml/1 l

= 1020 g/l

Mass of solution in 1 l of solution = 1020 g

Mass of solution = mass of solvent + mass of solute

Mass of sucrose = 1020 - 934.4

= 85.6 g of sucrose in 1 l of solution.

A.

Density of sucrose = mass/volume

= molar mass/molar concentration

= 342.296 * 0.25

= 85.6 g/l

Number of moles = mass/molar mass

= 85.6/342.296

= 0.25 mol

B.

Molality = number of moles of solute/mass of solvent

= 0.25/934.4

= 0.00027 mol/g

C.

% mass of sucrose = mass of sucrose/total mass of solution * 100

= 85.6/1020 * 100

= 8.39 %

6 0
2 years ago
Wat is diffrent from a square and trapisode
Vikki [24]
The main difference between a square and a trapezoid is that a square has two pairs of parallel sides, while a trapezoid only has one
4 0
3 years ago
Normally the capital ÎGo° for a reaction would be determined at standard temperature with each reactant at a concentration of 1
Arte-miy333 [17]

Answer:

d.-379 cal/mol

Explanation:

ΔG = ΔG⁰ + RT ln K

for equilibrium ΔG = 0

ΔG⁰ + RT ln K =0

ΔG⁰   =  -  RT ln K

PG ⇒ PEP

K = [ PEP ] / [ PG ]

= .68 / .32

= 2.125

ΔG⁰   =   - 1.987 x 273 x  ln 2.125

= - 409 Cal / mole

Option d is the nearest answer .

8 0
3 years ago
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