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3 years ago

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The system containing all the muscles of the body especially those involved in movement CONSIST of the three types of muscle ske

letal smooth and cardiac

1 answer:

Sunny_sXe [5.5K]3 years ago

3 0

The muscular system is involved in movement and has skeletal, smooth, and cardiac muscles

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What is the polystyrene?

Marta_Voda [28]

Answer:

Polystyrene is a versatile plastic used to make a wide variety of consumer products.

Explanation:

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2 years ago

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The equilibrium constant for the following reaction: H2(g) + Br2(g) ↔ 2HBr (g) is 1.65 x 103 at a certain temperature. Find the

Aleks [24]

Answer:

6.97 atm was the equilibrium pressure of HBr .

Explanation:

The value of the equilibrium constant = $K_p=1.65\times 10^3$

$H_2+Br_2\rightleftharpoons 2HBr$

Initially:

0 0 7.10 atm

At equilibrium

x x (7.10-2x)

The expression of equilibrium constant can be written as:

$K_p=\frac{p_{HBr}}{p_{H_2}\times p_{Br_2}}$

$1.65\times10^3=\frac{(7.10-2x)}{x^2}$

Solving for x:

x = 0.065

Partial pressure of HBr at equilibrium :(7.10 - 2 × 0.065) atm = 6.97 atm

6.97 atm was the equilibrium pressure of HBr .

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3 years ago

For this exercise, you can simulate the described conditions by changing the values in the run experiment tool of the simulation

Furkat [3]

1) ideal gas law: p·V = n·R·T.
p - pressure of gas.
V -volume of gas.
n - amount of substance.
R - universal gas constant.
T - temperature of gas.
n₁ = 0,04 mol, V₁ = 0,06 l.
n₂ = 0,07 mol, V₂ = 0,06 · 0,07 ÷ 0,04 = 0,105 l.
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T₂ = 340,00 K, V₂ = 340 · 0,06 ÷ 240 = 0,05 l.

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3 years ago

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Copper(II) carbonate undergoes thermal decomposition. One of the pro

Llana [10]

Answer: The green copper (II) carbonate $(CuCO_3)$ changes to black copper oxide $(CuO)$

$CuCO_3(s)\stackrel{\Delta }\rightarrow CaO(s)+CO_2(g)$

Explanation:

Decomposition is defined as the chemical reaction in which a single compound gives two or more simple substances. It requires energy to break the bonds between reactants, thus is an endothermic process.

Thermal decomposition uses heat for decomposition.

The chemical equation for thermal decomposition of copper (II) carbonate is:

$CuCO_3(s)\stackrel{\Delta }\rightarrow CaO(s)+CO_2(g)$

The green copper (II) carbonate $(CuCO_3)$ changes to black copper oxide $(CuO)$

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3 years ago

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