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Aloiza [94]
3 years ago
5

Help plz ? Mark brainliest?

Mathematics
1 answer:
Hoochie [10]3 years ago
8 0

Answer:

-1(3x^2) +4x-7

Step-by-step explanation:

grouping

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How do I factor trinomials of a form ax^2+bx+c when a=1 <br><br> In one paragraph
vitfil [10]

Answer:

  • Trinomials in the form x^2+bx+c can often be factored as the product of two binomials.

Step-by-step explanation:

As we know that a polynomial with three terms is said to be a trinomial.

Considering the trinomial of a form

ax^2+bx+c

As

a = 1

so

x^2+bx+c

  • Trinomials in the form x^2+bx+c can often be factored as the product of two binomials.

For example,

x^2+7x+10

=\left(x^2+2x\right)+\left(5x+10\right)

=x\left(x+2\right)+5\left(x+2\right)

\mathrm{Factor\:out\:common\:term\:}x+2

=\left(x+2\right)\left(x+5\right)

Therefore, Trinomials in the form x^2+bx+c can often be factored as the product of two binomials.

6 0
2 years ago
What's 5x3833 in an equation divided by two
Xelga [282]
You mean the answer of 5x3833 divided by two?

7 0
3 years ago
Fine the product:3 x 5 (2)
Delvig [45]

Answer:

30 because 3 x 5=15 then x2 it's 30

3 0
3 years ago
Okay now using distributive property write 2(4x-9) without parenthesis
riadik2000 [5.3K]
2(4x - 9) = 
2 * 4x - 2 * 9 = 
8x - 18

Hope this helps!!
~Kiwi


6 0
3 years ago
Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

8 0
3 years ago
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