Answer:
option D) -3m
Explanation:
if 6m is diplaced by -3m then it would be -3+6=3m
feel free to ask if you are confused
Answer:
Ff = 839.05 N
Explanation:
We can use the equation:
Ff = μ*N
where <em>N</em> can be obtained as follows:
∑ Fc = m*ac ⇒ N - F = m*ac = m*ω²*R ⇒ N = F + m*ω²*R
then if
F = 32 N
m = 133 Kg
R = 0.635 m
ω = 95 rev /min = (95 rev / min)(2π rad / 1 rev)(1 min / 60 s) = 9.9484 rad /s
we get
N = 32 N + (133 Kg)*(9.9484 rad /s)²*(0.635 m) = 8390.53 N
Finally
Ff = μ*N = 0.10*(8390.53 N) = 839.05 N
According to the <u>Third Kepler’s Law of Planetary motion</u> “<em>The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”.</em>
In other words, this law states a relation between the orbital period 
of a body (moon, planet, satellite) orbiting a greater body in space with the size 
of its orbit.
This Law is originally expressed as follows:
<h2>
(1)
</h2>
Where;
is the Gravitational Constant and its value is 
is the mass of Jupiter
is the semimajor axis of the orbit Io describes around Jupiter (assuming it is a circular orbit, the semimajor axis is equal to the radius of the orbit)
If we want to find the period, we have to express equation (1) as written below and substitute all the values:
<h2>
(2)
</h2>
Then:
<h2>
(3)
</h2>
Which is the same as:
<h2>
</h2>
Therefore, the answer is:
The orbital period of Io is 42.482 h
Answer:
A solenoid is a type of electromagnet, the purpose of which is to generate a controlled magnetic field through a coil wound into a tightly packed helix. The coil can be arranged to produce a uniform magnetic field in a volume of space when an electric current is passed through it.
The acceleration is 3 m/s per minute, or 0.05 m/s per second.
