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scoray [572]
3 years ago
9

Why was Rutherford's Gold Foil Experiment so important?

Chemistry
1 answer:
Oksanka [162]3 years ago
4 0

Answer:

Answer is 'B' I think

Explanation:

Rutherford's Gold Foil Experiment proved the existence of a small massive center to atoms, which would later be known as the nucleus of an atom. Through previous experiments of shooting alpha particles, Rutherford knew they had considerable mass and speed.

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Write 0.00000009345 in Engineering Notation with 3 significant figures
melisa1 [442]

Answer:

93.43\times 10^{-9}

Explanation:

Scientific notation is the way of writing numbers which are either large or small. The number is written in the scientific notation when the number is between 1 and 10 and then multiplied by the power of 10. Engineering notation is the same version of the scientific notation but the number can be between 1 and 1000 and in this exponent of the ten is divisible by three.

For example, 1000^2 is to be written as 10^6 in engineering notation.

The given number:

0.00000009345 can be written as 93.425\times 10^{-9}

Answer upto 4 significant digits = 93.43\times 10^{-9}

6 0
3 years ago
Be sure to answer all parts. For the complete redox reactions given here, write the half-reactions and identify the oxidizing an
OlgaM077 [116]

Answer : O_2 is the oxidizing agent and Fe is the reducing agent.

Explanation :

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The balanced redox reaction is :

4Fe+3O_2\rightarrow 2Fe_2O_3

The half oxidation-reduction reactions are:

Oxidation reaction : Fe\rightarrow Fe^{3+}+3e^-

Reduction reaction : O_2+4e^-\rightarrow 2O^{2-}

In order to balance the electrons, we multiply the oxidation reaction by 4 and reduction reaction by 3 then added both equation, we get the balanced redox reaction.

Oxidation reaction : 4Fe\rightarrow 4Fe^{3+}+12e^-

Reduction reaction : 3O_2+12e^-\rightarrow 6O^{2-}

4Fe+3O_2\rightarrow 2Fe_2O_3

In this reaction, 'Fe' is the reducing agent that loses an electron to another chemical species in a redox chemical reaction and itself gets oxidized and 'O_2' is the oxidizing agent that gain an electron to another chemical species in a redox chemical reaction and itself gets reduced.

Thus, O_2 is the oxidizing agent and Fe is the reducing agent.

7 0
3 years ago
what is Calcite's Solubility, I barely know what solubility mean let alone what it has to do with Calcite.
Ivahew [28]

Calcite can be either dissolved by groundwater or precipitated by groundwater, depending on several factors including the water temperature, pH, and dissolved ion concentrations. Although calcite is fairly insoluble in cold water, acidity can cause dissolution of calcite and release of carbon dioxide gas.

7 0
3 years ago
How much heat must be transferred to 100.0g of water to change its temperature by 35° C?
nekit [7.7K]

Answer:

14700J

Explanation:

From the question given, the following were obtained:

M = 100g

ΔT = 35° C

C = 4.2J/g °C

Q=?

The heat transferred can calculated for by using the following equation

Q = MCΔT

Q = 100 x 4.2 x 35

Q= 14700J

7 0
3 years ago
Arrange the compounds in order of decreasing magnitude of lattice energy:
Alik [6]

Answer:

The correct answer is CaO > LiBr > KI.

Explanation:

Lattice energy is directly proportional to the charge and is inversely proportional to the size. The compound LiBr comprises Li+ and Br- ions, KI comprises K+ and I- ions, and CaO comprise Ca²⁺ and O²⁻ ions.  

With the increase in the charge, there will be an increase in lattice energy. In the given case, the lattice energy of CaO will be the highest due to the presence of +2 and -2 ions. K⁺ ions are larger than Li⁺ ion, and I⁻ ions are larger than Br⁻ ion.  

The distance between Li⁺ and Br⁻ ions in LiBr is less in comparison to the distance between K⁺ and I⁻ ions in KI. As a consequence, the lattice energy of LiBr is greater than KI. Therefore, CaO exhibits the largest lattice energy, while KI the smallest.  

8 0
4 years ago
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