Answer: 38L
Explanation:
Initial volume of helium V1 = 35 L
Initial temperature T1 = 20°C
Convert temperature in Celsius to Kelvin
(20°C + 273 = 293K)
New volume V2 = ?
New Temperature T2 = 45°C
(45°C + 273 = 318K)
Since, volume and temperature are involved while pressure is constant, apply the formula for Charles' Law:
(V1/T1) = (V2/T2)
35L/293K = V2/318K
0.119 = V2/318K
To get V2, cross multiply
V2 = 0.119 x 318
V2 = 38L
Thus, the new volume of the balloon is 38 liters
