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Ivan
3 years ago
12

A balloon is filled with 35L of helium in the morning when the temperature is 20C. By noon the temperature has risen to 45C. Wha

t is the new volume of the balloon?
Chemistry
1 answer:
neonofarm [45]3 years ago
8 0

Answer: 38L

Explanation:

Initial volume of helium V1 = 35 L

Initial temperature T1 = 20°C

Convert temperature in Celsius to Kelvin

(20°C + 273 = 293K)

New volume V2 = ?

New Temperature T2 = 45°C

(45°C + 273 = 318K)

Since, volume and temperature are involved while pressure is constant, apply the formula for Charles' Law:

(V1/T1) = (V2/T2)

35L/293K = V2/318K

0.119 = V2/318K

To get V2, cross multiply

V2 = 0.119 x 318

V2 = 38L

Thus, the new volume of the balloon is 38 liters

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As we get to know that it is easy to obtain metals from their oxides. So, firstly ores which is found in the form of carbonates and sulphide are converted into their oxides by using the process of calcination and roasting.

The metals which is in the middle of the activity series are moderately reactive. These metals are found in the crust of the earth is mainly found as oxides, sulphides, or carbonates.

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  • This enrichment is done commercially using centrifuges filled with gaseous uranium.
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The two isotopes of uranium that are most commonly found in nature are U-235 and U-238. The 'fission' or breaking of the U-235 atoms, which releases energy in the form of heat, is how nuclear reactors generate energy. The primary fissile isotope of uranium is U-235.

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Although uranium-235 and uranium-238 are chemically identical, they have different physical characteristics, most notably mass. The U-235 atom has an atomic mass of 235 units due to its 92 protons and 143 neutrons in its nucleus. The U-238 nucleus has 146 neutrons—three more than the U-235 nucleus—in addition to its 92 protons, giving it a mass of 238 units.

The isotopes may be separated due to the mass difference between U-235 and U-238, which also makes it possible to "enrich" or raise the proportion of U-235. This slight mass difference is used, directly or indirectly, in all current and historical enrichment procedures.

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