CaBr2(s) Ca+2(aq)+2Br-(aq) which means, <span>Solid is turning into free ions so entropy is increasing .</span>
A chemical structure of a molecule includes the arrangement of atoms and the chemical bonds that hold the atoms together. The 2-HEPTANONE molecule contains a total of 21 bond(s) There are 7 non-H bond(s), 1 multiple bond(s), 4 rotatable bond(s), 1 double bond(s) and 1 ketone(s) (aliphatic).
Answer: hen a solution is very acidic, what does it have a high concentration of?
Hydroxide (OH-)
Hydronium (H3O+)
Iodide (I-)
Acetate(C2H3O2-)
Explanation:
Answer:
The balanced equation is: H2 (g) +Cl2 (g) →2HCl (g)
Explanation:
Balancing chemical equation refers to balancing the stoichiometric coefficients on the reactants and products side. This must be done as the chemical equation obeys the law of conservation of mass and momentum.
The representation of a chemical reaction in the form of substances is known as a chemical equation. The equation in which the number of atoms of all the molecules is equal on both sides of the equation is known as a balanced chemical equation. The Law of conservation of mass governs the balancing of a chemical equation.
Given chemical equation
The balanced chemical equation for the hydrogen + chlorine -> Hydrogen Chloride.
H2 + Cl2 → 2HCl
The equation is balanced as on the reactants side there are two hydrogens present and the same on the products side. For chlorine as well the same thing goes two chlorine atoms on the reactants side and two on the products side.
Answer:
7.81 moles
Explanation:
To solve this problem, let us generate an expression involving volume and number of mole of the gas since the pressure and temperature of the gas are constant.
From ideal gas equation:
PV = nRT
Divide both side by P
V= nRT/P
Divide both side by n
V/n = RT/P
Since RT/P are constant, then:
V1/n1 = V2/n2
Data obtained from the question include:
V1 = 4.11
n1 = 2.51 moles
V2 = 16.9L
n2 =?
Using the above equation i.e V1/n1 = V2/n2, the final number of the gas can be obtained as illustrated below:
4.11/2.51 = 16.9/n2
Cross multiply to express in linear form
4.11 x n2 = 2.51 x 16.9
Divide both side by 4.11
n2 = (2.51 x 16.9) / 4.11
n2 = 10.32moles
Now, to obtain the number of mole of the gas added, we'll subtract the initial mole from the final mole i.e
n2 — n1
Number of mole added = n2 — n1
10.32 — 2.51 = 7.81 moles
Therefore, 7.81 moles of the gas was added to the container
