Answer:
The mass percentage of bromine in the original compound is 81,12%
Explanation:
<u>Step 1: Calculate moles AgBr</u>
moles AgBr = mass AgBr / molar mass AgBr
= 0.8878 g / 187.77 g/mol
= 0.00472812 moles AgBr
⇒
Since 1 mol AgBr contains 1 mol Br-
Then the amount of moles Br- in the original sample must also have been 0.00472812 moles
<u>Step 2:</u> Calculating mass Br-
mass Br- = molar mass Br x moles Br-
= 79.904 g/mol x 0.00472812 mol
= 0.377796 g Br-
⇒
There were 0.377796 g Br- in the original sample
<u>Step 3:</u> Calculating mass percentage Br-
⇒mass percentage = actual mass Br- / total mass x 100%
% mass Br = 0.377796 g / 0.4657 g x 100 %
= 81.12%
<u>Answer:</u> The volume of given mas of tin block at STP is 
<u>Explanation:</u>
To calculate volume of of the substance, we use the equation:

We are given:
Mass of tin = 95.04 g
Density of tin = 
Putting values in above equation, we get:

Hence, the volume of given mas of tin block at STP is 
Hey there!:
Isotopes : abundance :
46 Ti 8.0%
47 Ti 7.8 %
48 Ti 73.4 %
49 Ti 5.5 %
50 Ti 5.3 %
Weighted average = ∑ Wa * % / 100
Therefore:
( 46 * 8.0) + (47 * 7.8 ) + (48 * 73.4 ) + ( 49 * 5.5 ) + ( 50*5.3 ) / 100 =
4792.3 / 100
= 47.923 a.m.u
Hope that helps!
Answer:
The answer is OXIDATION REACTION.
Answer:
Time = t = 30.01 minutes
Explanation:
The missing part of the question is that "The water heater power rating is 255 Watts, where 1 Watt = 1 J/s.
Firstly, calculating the work done by water heater to heat 5.5 L of water from 23° C to 43°C.
Work Done = Q = m C ΔT
where,
Q = Heat Transfer
m = mass of water
m = Density x Volume = 1 g/mL x 5.5 L = 1000g/L x 5.5L = 5500 g
ΔT = Temperature Difference = 43-23 = 20°C
C = Heat Capacity of Water = 4.186 J/g °C
Therefore,

Since, Power can be given as Work done per unit time,

or, in this case,

Here,
P = 255W or P = 255J (Since 1W = 1J)
