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blagie [28]
3 years ago
9

Similarities between temperature and heat energy.

Physics
1 answer:
almond37 [142]3 years ago
3 0
Temperature IS heat energy. They are the same exact thing.
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Some city officials recommend using EZVI because the process treats contaminated water. Consider
Sindrei [870]

Access to Alternative Source of Fuel.

Reduce Surface Toxicity.

Lower Energy Cost.

More Jobs.

Buys More Time.

Requires Huge Amounts of Water.

Possible Water Contamination.

May Trigger Earthquakes.

6 0
3 years ago
Please answer :( gravity question for science
andreev551 [17]

The two forces acting on your body are the weight and the normal  force

Explanation:

As you sit on your chair in front of the computer, there are 2 forces acting on you:

  • The force of gravity, of magnitude mg (where m is your mass and g=9.8 m/s^2 is the acceleration of gravity), acting downward
  • The normal reaction exerted by the chair on your body, N, acting upward, and balancing your weight

We can apply Newton's second law to this situation; the law states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:

\sum F = ma

where

\sum F is the net force

m is the mass

a is the acceleration

For your body sitting on the chair,

\sum F = N-mg

we also know that your body is at rest, so the acceleration is zero:

a=0

This means that the net force is zero, and therefore:

\sum F = 0 =N-mg\\\rightarrow N = mg

Learn more about Newton's second law of motion:

brainly.com/question/3820012

#LearnwithBrainly

8 0
3 years ago
A cube of wood having an edge dimension of 18.0 cm and a density of 651 kg/m3 floats on water.(a) What is the distance from the
astra-53 [7]

Answer:

A. 6.282

B. 2.03kg

Explanation:

A.

We solve using archimedes principle

L³pwood = L²dwater

We make d subject of the formula

d = Lpwood/pester

= 18x651/1000

= 18x0.651

= 11.718cm

Distance from horizontal top to water level

= 18-11.718

= 6.282cm

B.

When we place lead block

WL + L³pwoodg = L³pwaterg

WL = L³g(Pwater-Pwood)

= 0.18³x9.8(1000-651)

= 19.94N

19.94/9.8

= 2.03kg

The mass m is therefore 2.03kg

6 0
3 years ago
White light (400–700 nm) is incident on a 600 line/mm diffraction grating. What is the width of the first-order rainbow on a scr
Tema [17]

Answer:

Δy=0.431m

Explanation:

Diffraction grating with split space d,to find the fringe position ym,we must to find the angle from

dSinα=mλ

A grating with N slits or lines per mm has slit spacing of

d=1/N

d=(1/600mm)

d=1.67×10⁻³mm

For 400nm wavelength:

α=Sin⁻¹(mλ/d)

\alpha =Sin^{-1}(\frac{400*10^{-9} }{1.67*10^{-6}} )\\ \alpha =13.910^{o}

And the position of first order lowest wavelength fringe on the screen is:

y_{1}=Ltan\alpha_{1}\\y_{1}=2tan(13.910)\\  y_{1}=0.49445m

For 700nm wavelength:

α=Sin⁻¹(mλ/d)

\alpha =Sin^{-1}(\frac{700*10^{-9} }{1.67*10^{-6}} )\\ \alpha_{2}  =24.83^{o}

And the position of first order highest wavelength fringe on the screen is:

y_{2}=Ltan\alpha_{2}\\y_{2}=2tan(24.83)\\  y_{2}=0.925595m

The difference between the first order lowest and highest wavelength fringe is

Δy=(0.925595 - 0.49445)m

Δy=0.431m

6 0
4 years ago
A mass of 5 kg is placed at rest on a horizontal surface with a coefficient of static friction of 1.03 and a coefficient of kine
IgorLugansk [536]
Until the object starts to move, the static coefficient of friction must be used since the object is at rest initially.  If the horizontal force is large enough to overcome the friction force and the object accelerates, we switch to the kinetic coefficient.
The total downward force in the -y direction is the weight plus the applied 26N:
Fy=mg-26N = 5*-9.81-26 = -75.05N
The maximum friction force here is the magnitude of this force times the static coefficient of friction.  This force will point in the opposite direction as an applied horizontal force, no matter which way it points (non conservative forces tend to oppose motion in all directions)
Ff=75.05N*1.03=77.3N
Note this is greater than the applied horizontal x-directed force of 26N.  This means the answer is 26N of friction force acting on the object.  Why not the full 77.3N?  Because that is the maximum amount you can oppose along the x-direction before the object starts to move.  But since we are only applying 26N, that is all the friction force pushes back with. This is a statement of Newton's 3rd Law of equal and opposite actions.  If the object pushed back with the full 77.3N in this case it would accelerate backward (F=ma), since there would be a net force on the object (77.3N - 26N = 51.3N)  This obviously doesn't happen!
4 0
4 years ago
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