A 90-g bead is attached to the end of a 60-cm length of massless string. The other end of the string is held at point O, which i
s 200 cm above the floor, and the bead is swung counterclockwise at a constant speed in a vertical circle. The tension in the string when the bead is at the very bottom of the circle is 2.2 N. While the bead is in motion, a very sharp knife is inserted to cut the string directly below point O. How far to the right of the center of the circle does the bead hit the floor?
1 answer:
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Answer:
The pressure increases by a factor 8
Explanation:
For a gas held at constant temperature, Boyle's law can be applied. It states that the product of the gas pressure and the gas volume is constant, so we can write:
where
is the initial pressure
is the final pressure
is the initial volume
is the final volume
For the gas in this problem, the volume is reduced from
to
so we can rewrite the equation as
this means that the pressure of the gas will increase by a factor 8.
Answer:
A point on the outside rim will travel 157.2 meters during 30 seconds of rotation.
Explanation:
We can find the distance with the following equation since the acceleration is cero (the disk rotates at a constant rate):
Where:
v: is the tangential speed of the disk
t: is the time = 30 s
The tangential speed can be found as follows:
Where:
ω: is the angular speed = 100 rpm
r: is the radius = 50 cm = 0.50 m
Now, the distance traveled by the disk is:
Therefore, a point on the outside rim will travel 157.2 meters during 30 seconds of rotation.
I hope it helps you!