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Tresset [83]
3 years ago
10

When comparing the colors of the following four compounds, which is most likely to appear green? [Co(CN)6]3− [Co(H2O)6]3+ [Co(en

)3]3+ [CoI6]3− and why?
Chemistry
2 answers:
Wewaii [24]3 years ago
8 0

Answer:

[Co(H2O)6]3 is most likely to appear green,because of it physical nature and ph values.

alexandr1967 [171]3 years ago
5 0

Answer:

3

Explanation:

its bc

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Answer:

1: 2-bromo-3-chloropentane

Explanation:

find longest carbon chain =5

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follow naming rules I guess

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Determine if each of the following statements about chiral molecules is True or False and select the best answer from the dropdo
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Answer:

See explanation

Explanation:

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The absolute configuration is based is in specific rules that are not related to the ability to deflect polarized light. <u>FALSE</u>

-)<u> True or False: Chiral centers in organic molecules will have 4 different groups attached to a carbon. </u>

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A chiral carbon by definition is a carbon with 4 groups. <u>TRUE</u>

-)<u> True or False: A racemic mixture has an optical activity of 0. </u>

In a racemic mixture, we have equal amounts of enantiomers, and this cancels out the optical activity. <u>TRUE</u>

-)<u> True or False: Normal linear amines can be chiral centers. </u>

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In primary amines, we have 2 hydrogens. Therefore all the groups can not be different. So, is <u>TRUE</u>

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-)<u>True or False: Compound C has an optical activity of 0. </u>

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We need to know the structure of the compound

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-)<u>True or False: If the R isomer of a molecule has an optical rotation of + 25.7 degree then the S isomer of the molecule will have an optical rotation of -25.7 degree. </u>

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If we have the exact opposite (as we have in this case) the magnitud of the optical activity value will remain and the sign will change. <u>TRUE</u>

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In this case, a carbon is directly bonded to the chiral carbon. The carbon on CN is bonded to a nitrogen atom and the carbon on CH2OH is bonded to an oxygen. So, the CH2OH will have more priority because O has a higher atomic number. <u>FALSE</u>

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-)<u>True or False: All molecules with chiral centers are optically active. </u>

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We can have for example mesocompounds in which the optical activity is canceled out due to symmetry planes. <u>FALSE</u>

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-)<u>True or False: To have an enantiomer a molecule must have at least two chiral centers. </u>

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A pair of enantiomers is made between at least 1 chiral carbon. Enantiomer R and enantiomer S. <u>FALSE</u>

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We can have racemic mixtures or mesocompounds with chiral carbons but without optical activity. <u>FALSE</u>

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<u>True or False: Diastereomers have the same physical properties except in a chiral environment. </u>

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Answer:

Explanation:

Let's try and figure out the ones you don't keep.

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Now figure out which ones you would want to keep

1. Anything pertaining to medical perscriptions. I don't know how it works in the United States, but in Canada we are allowed to deduct only medications with a DIN number.

2 Anything that you would use for travelling that is not for pleasure (ie it is a business expense). So if you are a salesman and your territory is from A to B you would deduct meals, mileages, motels if you must stay away from home

3 In the states some tax receipts are deductible, so you might want to save those.

6 0
2 years ago
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Masteriza [31]
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3 years ago
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