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HACTEHA [7]
3 years ago
14

49 more than the quotient of an unknown number and 12 is 53. What is the value of the unknown number?

Mathematics
1 answer:
lara [203]3 years ago
4 0
Unknown = x

the quotient of x and 12 is x/12 than 49 more than that is 53,
(x/12)+49=53, now use basic math and solve

-49 from both side,
x/12=4

*12 to both side,
x=48

therefore the unknown number is 48

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What statement is true?
givi [52]

Answer:

\frac{18}{32}>\frac{16}{32}

Step-by-step explanation:

We need to find which statements are true.

Solution to find the same we will solve each statement and will conclude the same.

1.  \frac{14}{21}>\frac{17}{24}

Now On solving we get;

\frac{14}{21} = 0.66

\frac{17}{24}=0.70

So we can see that 0.70 > 0.66

Hence The given statement is False.

2. \frac{18}{32}>\frac{16}{32}

Now On solving we get;

\frac{18}{32}=0.5625

\frac{16}{32}= 0.5

So we can see that 0.5625 > 0.5

Hence The given statement is True.

3.  \frac{20}{15}

Now On solving we get;

\frac{20}{15} = 1.33

\frac{28}{23}=1.2

So we can see that 1.33 > 1.2

Hence The given statement is False.

4.  \frac{29}{35}

Now On solving we get;

\frac{29}{35}= 0.82

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So we can see that 0.82 > 0.66

Hence The given statement is False.

7 0
3 years ago
I need help with my math
mrs_skeptik [129]

Answer:

A=28

B=18

C=18

D=28

E=28

F=18

G=10

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Step-by-step explanation:

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2 years ago
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fiasKO [112]

Answer:

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7 0
3 years ago
Read 2 more answers
A quadratic equation is shown below:
sweet [91]

Answer:

Part A:

( 1.8333, -0.08333)

Part B:

x = 2 or x = 5/3

Step-by-step explanation:

The quadratic equation

3x^{2}-11x+10=0 has been given.

Part A:

We are required to determine the vertex. The vertex is simply the turning point of the quadratic function. We shall differentiate the given quadratic function and set the result to 0 in order to obtain the co-ordinates of its vertex.

\frac{d}{dx}(3x^{2}-11x+10)=6x-11

Setting the derivative to 0;

6x - 11 = 0

6x = 11

x = 11/6

The corresponding y value is determined by substituting x = 11/6 into the original equation;

y = 3(11/6)^2 - 11(11/6) + 10

y = -0.08333

The vertex is thus located at the point;

( 1.8333, -0.08333)

Find the attached

Part B:

We can use the quadratic formula to solve for x as follows;

The quadratic formula is given as,

x=\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}

From the quadratic equation given;

a = 3, b = -11, c = 10

We substitute these values into the above formula and simplify to determine the value of x;

x=\frac{11+/-\sqrt{11^{2}-4(3)(10) } }{2(3)}=\frac{11+/-\sqrt{1} }{6}\\\\x=\frac{11+/-1}{6}\\\\x=\frac{11+1}{6}=2\\\\x=\frac{11-1}{6}=\frac{5}{3}

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What’s the question ?
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3 years ago
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