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3 years ago

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If, in a peptide chain, there were 85 amino acids each joined by peptide bonds, how many n-terminus groups would be present?

1 answer:

Crank3 years ago

8 0

If, in a peptide chain, there were 85 amino acids each joined by peptide bonds, there would only be 1 N-terminus group that would be present. The N-terminus group is always the start of the chain of a amino acid chain or a protein or a polypeptide. It refers to the free amine group present that is located at the end part of the chain. So, that no matter how many amino acids in a chain there would always be only one N-terminus group.

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When 74.8g of alanine C3H7NO2 are dissolved in 1450.g of a certain mystery liquid X, the freezing point of the solution is 8.30°

dlinn [17]

Answer: The mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=8.30^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

$K_f$ = freezing point constant =

m= molality = $\frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}=\frac{74.8g\times 1000}{1450g\times 89.09g/mol}=0.579$

$8.30^0C=1\times K_f\times 0.579$

$K_f=14.3^0C/m$

Let Mass of solute (KBr) = x g

$8.3^0C=1.72\times 14.3\times \frac{xg\times 1000}{119g/mol\times 1450g}$

$x=58.2g$

Thus the mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

7 0

2 years ago

Describe how the size of sediment particles affects their movement during deflation.

Oksi-84 [34.3K]

The larger the piece the longer it will take to break down. This is because it has more mass that needs to be broken down.

6 0

3 years ago

Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 4.90 moles of magnesium perchlorate, Mg(ClO4)2.]\

Leviafan [203]

Answer:

4.90 moles of $Mg(ClO_4)_2$ will produce (9.8) moles of $Cl^{-}$ ,

(4.90) moles of $Mg^{2+}$ and

(39.2) moles of $O^{2-}$

Explanation:

From the question we are told that

The number of moles of is $n = 4.90 \ mols$

The formation reaction of $Mg(ClO_4)_2$ is

$Mg^{2+} + 2 Cl^{-} + 8O^{2+} \to Mg(ClO_4)_2$

From the reaction we see that

1 mole of $Mg(ClO_4)_2$ is formed by 2 moles of $Cl^{-}$ 1 mole of $Mg^{2+}$ and 4 $O^{2-}$

This implies that

4.90 moles of $Mg(ClO_4)_2$ will produce (2 * 4.90) moles of $Cl^{-}$ ,

(1 * 4.90) moles of $Mg^{2+}$ and

(8 * 4.90) moles of $O^{2-}$

So

4.90 moles of $Mg(ClO_4)_2$ will produce (9.8) moles of $Cl^{-}$ ,

(4.90) moles of $Mg^{2+}$ and

(39.2) moles of $O^{2-}$

4 0

3 years ago

Read 2 more answers

Picture shown! <br><br> At 3 mmHg and 500C water exists as a<br> Liquid<br> Solid<br> Gas

mestny [16]

Answer:

At 3 mmHg and 50°C water exists as a <em><u>gas</u></em>.

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3 years ago

What major component of water affects most its properties?

Alona [7]

Answer:

C. polarity

Explanation:

Water is polar that is why it is a universal solvent.

8 0

2 years ago