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Juli2301 [7.4K]
2 years ago
12

How much heat must be removed from 456 g of water at 25. 0 c to hcange it into ice at 10 c

Chemistry
1 answer:
ValentinkaMS [17]2 years ago
6 0

The heat required to convert water is given as the product of the mas and the latent heat. 28.34 kJ heat must be removed from the water to change it into ice.

<h3>What is heat energy?</h3>

Heat energy is the product of mass, specific heat capacity, and temperature change. It is given as,

\rm Q = mc \Delta T

Given,

Mass of water = 456 gm

Specific heat capacity = 4.186 J / g K

Temperatutre change = 14.85 K

Substituting values above:

\begin{aligned} \rm Q &= 456 \times 4.186 \times 14.85\\\\&= 28345.91\;\rm J\\\\&= 28.34\;\rm kJ\end{aligned}

Therefore, 28.34 kJ of heat energy should be removed from the water.

Learn more about the heat here:

brainly.com/question/14052023

#SPJ4

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A student is determining the density of an unknown metal with a mass of 32.56 g. The student partially fills a graduated cylinde
xenn [34]

Answer:

The metal is Tin (Sn)

Explanation:

The following data were obtained from the question:

Mass of metal = 32.56 g

Volume of water = 14.78 mL

Volume of water + metal = 20.44 mL

Next, we shall determine the volume of the metal. This is illustrated below:

Volume of water = 14.78 mL

Volume of water + metal = 20.44 mL

Volume of metal =..?

Volume of metal = (Volume of water + metal) – (Volume of water )

Volume of metal = 20.44 – 14.78

Volume of metal = 5.66mL

Next, we shall determine the density of the metal.

Density of a substance is defined as the mass of the substance per unit volume of the substance. Mathematically, the density of a substance is expressed as:

Density = Mass / volume

With the above formula, we can obtain the density of the metal as follow:

Mass of metal = 32.56 g

Volume of metal = 5.66mL

Density =.?

Density = Mass /volume

Density = 32.56g/5.66mL

Density of the metal = 5.75g/mL

Comparing the density of the metal with standard density of elements, the metal is Tin (Sn)

4 0
3 years ago
0.750mol of gas are stored in a tank at a pressure of 275kpa and a temperature of 0.00 degrees * C What is the volume of the tan
nordsb [41]

Answer:

The volume on the tank is 6, 20 L

Explanation:

We use the formula PV=nRT. We convert the units of pressure in kPa into atm and temperature in Celsius into Kelvin:

0°C=273K

101,325kPa---1 atm

275kPa --------x=(275kPax 1 atm)/101,325kPa= 2,71 atm

PV=nRT --> V=nRT/P

V= 0,750 mol x 0,082 l atm /K mol x 273 K/ 2, 71 atm= <em>6, 20 L</em>

4 0
3 years ago
Which two radioisotopes have the same decay mode
Olin [163]
37Ca and 53Fe I believe ..
5 0
3 years ago
what is the balanced equation of magnesium carbonate decomposes on heating to form magnesium oxide and carbon dioxide​
fenix001 [56]

Answer:

ExplaAt high temperatures MgCO3 decomposes to magnesium oxide and carbon dioxide. This process is important in the production of magnesium oxide. This process is called calcining: MgCO3 → MgO + CO2 (ΔH = +118 kJ/mol)

nation:

6 0
3 years ago
sa solution is made by dissolving 26.42 g of (NH4)2SO4 in enough H2O to make 50.00 mL of solution. what is the molarity of the s
krok68 [10]
The answer is 0.2 M.

Molarity is a measure of the concentration of solute in a solution

c = n ÷V<span>
c - concentration of solute,
n - number of moles of solute
V - volume of solution

</span>

We know:

V = 50.00 mL = 0.05 L

c = ?

n = ?


Let's calculate concentration:

c = m/(V * Mr)


The molar mass of <span>(NH4)2SO4 is the sum of atomic masses (Ar) of its elements):
Mr (</span><span>(NH4)2SO4) = 2Ar(N) + 8 Ar(H) + Ar(S) + 4Ar(O)
                           = 2 * 14 + 8 * 1 + 32 + 4 * 16 =
                           = 28 + 8 + 32 + 64 = 
                           = 132 g/mol

c = 26.42 g/ (0.05 L * 132g /mol) =26.42 g/ 6.6 L*g/mol = 4 mol/L = 4 M

Now, calculate molarity:
</span>c = n ÷V
n = c * V
n = 4 mol/L * 0.05 L
n = 0.2 mol
4 0
3 years ago
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