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2 years ago

How much heat must be removed from 456 g of water at 25. 0 c to hcange it into ice at 10 c

1 answer:

6 0

The heat required to convert water is given as the product of the mas and the latent heat. 28.34 kJ heat must be removed from the water to change it into ice.

<h3>What is heat energy?</h3>

Heat energy is the product of mass, specific heat capacity, and temperature change. It is given as,

$\rm Q = mc \Delta T$

Given,

Mass of water = 456 gm

Specific heat capacity = 4.186 J / g K

Temperatutre change = 14.85 K

Substituting values above:

$\begin{aligned} \rm Q &= 456 \times 4.186 \times 14.85\\\\&= 28345.91\;\rm J\\\\&= 28.34\;\rm kJ\end{aligned}$

Therefore, 28.34 kJ of heat energy should be removed from the water.

Learn more about the heat here:

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