How much heat must be removed from 456 g of water at 25. 0 c to hcange it into ice at 10 c
1 answer:
The heat required to convert water is given as the product of the mas and the latent heat. 28.34 kJ heat must be removed from the water to change it into ice.
<h3>What is heat energy?</h3>Heat energy is the product of mass, specific heat capacity, and temperature change. It is given as,
Given,
Mass of water = 456 gm
Specific heat capacity = 4.186 J / g K
Temperatutre change = 14.85 K
Substituting values above:
Therefore, 28.34 kJ of heat energy should be removed from the water.
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Hello!
The reaction that the graph represents is A. Exothermic because Hrxn=-167 kJ
To calculate Hrxn we apply the following equation:
Looking at the graph, and at the result of the calculations, we can see that the enthalpy of the products is lower than the enthalpy of the reagents, because the sign is negative. That means that the reaction releases energy in the form of heat and that the reaction is exothermic.
Have a nice day!
The reaction that the graph represents is A. Exothermic because Hrxn=-167 kJ
To calculate Hrxn we apply the following equation:
Looking at the graph, and at the result of the calculations, we can see that the enthalpy of the products is lower than the enthalpy of the reagents, because the sign is negative. That means that the reaction releases energy in the form of heat and that the reaction is exothermic.
Have a nice day!