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sasho [114]
3 years ago
13

Describe how to use physical properties to seperate a mixture of ice cubes and nails

Chemistry
1 answer:
Marrrta [24]3 years ago
4 0
The magnetic property of nails could be used to just pull them out with a magnet.
The difference in boiling points between water and iron or steel is hundreds of degrees Celsius so you could apply heat and just boil the water away.
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"A group of college students believes that herbal tea has remarkable restorative powers. To test their belief, they visit a loca
Georgia [21]

D) the college students

Explanation:

In the experiment conducted by staffs of the nursing home, the group of college students that came for the experiment are the subjects of the experiment. A subject is a person that participates in a research.

  • In this research, the college students are the human participants in the experiment.
  • There must be a mutual agreement between the researcher and the subject because the subject is one that is being tested to see an outcome.
  • A subject can quit a research if he/she deems it fit at any time.

Learn more:

Experiments brainly.com/question/5096428

#learnwithBrainly

7 0
3 years ago
A reaction was performed in which 3.6 g 3.6 g of benzoic acid was reacted with excess methanol to make 1.3 g 1.3 g of methyl ben
Anit [1.1K]

<u>Answer:</u> The percent yield of the reaction is 32.34 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For benzoic acid:</u>

Given mass of benzoic acid = 3.6 g

Molar mass of benzoic acid = 122.12 g/mol

Putting values in equation 1, we get:

\text{Moles of benzoic acid}=\frac{3.6g}{122.12g/mol}=0.0295mol

The chemical equation for the reaction of benzoic acid and methanol is:

\text{Benzoic acid + methanol}\rightarrow \text{methyl benzoate}

By Stoichiometry of the reaction

1 mole of benzoic acid produces 1 mole of methyl benzoate

So, 0.0295 moles of benzoic acid will produce = \frac{1}{1}\times 0.0295=0.108 moles of methyl benzoate

  • Now, calculating the mass of methyl benzoate from equation 1, we get:

Molar mass of methyl benzoate = 136.15 g/mol

Moles of methyl benzoate = 0.0295 moles

Putting values in equation 1, we get:

0.0295mol=\frac{\text{Mass of methyl benzoate}}{136.15g/mol}\\\\\text{Mass of methyl benzoate}=(0.0295mol\times 136.15g/mol)=4.02g

  • To calculate the percentage yield of methyl benzoate, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of methyl benzoate = 1.3 g

Theoretical yield of methyl benzoate = 4.02 g

Putting values in above equation, we get:

\%\text{ yield of methyl benzoate}=\frac{1.3g}{4.02g}\times 100\\\\\% \text{yield of methyl benzoate}=32.34\%

Hence, the percent yield of the reaction is 32.34 %

6 0
3 years ago
What is the balanced form of the chemical equation shown below?<br> N2(g) + H2(g) → NH3(g)<br> -
Rom4ik [11]
To balance equations you have to have same number of atoms on both sides of the equation just multiply with a suitable digit

6 0
2 years ago
Draw the curved arrow mechanism for the formation of an acetal from acidic methanol and 4-methylpentan-2-one in the fewest steps
morpeh [17]

Answer:

See explanation below

Explanation:

This reaction is known as Ketone hydrolisis in acid medium. This involves the formation of an hemi cetal, and then, the acetal. This is often used to convert ketones or aldehydes in ethers.

The first step involves the reaction with the acid. The carbonile reacts with the acid and forms an alcohol there. The next step is the reaction of the alcohol, in this case, the methanol to form the hemi cetal. Then in the third step, we repeat the first step, using acid to turn the OH group into a great leaving group such water. Then the water leaves the molecule, leaving the space wide open in the next step for methanol, and the acetal is formed.

See picture for the curved arrow mechanism

7 0
3 years ago
How many atoms of hydrogen and oxygen are present in 5 gm of HNO3
Rufina [12.5K]
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6 0
3 years ago
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