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3 years ago

Kelli and Karl each have a job. Kelli earns $20 an hour. She also receives a $100 weekly bonus.

Mathematics

2 answers:

ad-work [718]3 years ago

7 0

Equation for Kelli's earning = 20x + 100
Equation for Karl's earning = 25x + 50

Now, 20x +100 = 25x +50
25x-20x = 100-50
5x = 50
x = 10

So, your answer is 10 hours.

Hope this helps!

Gnesinka [82]3 years ago

7 0

20h+100=25h+50
20h+50=25h
50=5h
10=h
They must work 10 hours a week to earn the same amount.

Hope this helps :)

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Read 2 more answers

two leaky containers are filling with water. water enters container a at a rate of 2/3 cup per 1/2 minute and leaks out at a rat

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container B needs to be filled faster in order for both containers to gain the same amount of water per minute , and by 1/6 water per minute .

<u>Step-by-step explanation:</u>

Here we have , two leaky containers are filling with water. water enters container a at a rate of 2/3 cup per 1/2 minute and leaks out at a rate of 1/4 cup per 3/4 minute. water enters container b at a rate of 3/4 cup per 1/2 minute and leaks out at a rate of 1/2 cup per 3/4 minute. We need to find which container needs to be filled faster in order for both containers to gain the same amount of water per minute . Let's find out:

Rate of Filling container A:

⇒ $\frac{\frac{2}{3} }{\frac{1}{2} }$

⇒ $\frac{2}{3} (2) = \frac{4}{3}$

Rate of leaking Container A:

⇒ $\frac{\frac{1}{4} }{\frac{3}{4} }$

⇒ $\frac{1}{4} (\frac{4}{3}) = \frac{1}{3}$

Amount of water in Container A in one minute :

⇒ $\frac{4}{3} - \frac{1}{3} = 1$

No , following same for Container B

Rate of Filling container B:

⇒ $\frac{\frac{3}{4} }{\frac{1}{2} }$

⇒ $\frac{3}{4} (\frac{2}{1}) = \frac{3}{2}$

Rate of leaking Container B:

⇒ $\frac{\frac{1}{2} }{\frac{3}{4} }$

⇒ $\frac{1}{2} (\frac{4}{3}) = \frac{2}{3}$

Amount of water in Container B in one minute :

⇒ $\frac{3}{2} - \frac{2}{3} = \frac{5}{6}$

Since , Rate of water per minute in container A is 1 and , Rate of water per minute in container B is 5/6 , container A fills faster by container B by

⇒ $1-\frac{5}{6} = \frac{1}{6}$

Therefore , container B needs to be filled faster in order for both containers to gain the same amount of water per minute , and by 1/6 water per minute .

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