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jek_recluse [69]
3 years ago
9

When the following reaction comes to equilibrium, will the concentrations of the reactants or products be greater? Does the answ

er to this question depend on the initial concentrations of the reactants and products? A(g)+B(g)⇌2C(g)Kc=1.4×10−5 Match the words in the left column to the appropriate blanks in the sentences on the right. ResetHelp The value of the equilibrium constant is relatively ; therefore, the concentration of reactants will be the concentration of products. This result is the initial concentration of the reactants and products.
Chemistry
1 answer:
Nutka1998 [239]3 years ago
4 0

Answer:

At equilibrium, the concentration of the reactants will be greater than the concentration of the products. This does not depend on the initial concentrations of the reactants and products.

Explanation:

The value of Kc gives us an idea of the extent of the reaction. A big Kc (Kc > 1) means that in the equilibrium there are more products than reactants, and the opposite happens for a small Kc (Kc < 1). The equilibrium is reached no matter what the initial concentrations are.

The value of the equilibrium constant is relatively SMALL; therefore, the concentration of reactants will be GREATER THAN the concentration of products. This result is INDEPENDENT OF the initial concentration of the reactants and products.

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From the scientist's results after testing the water for nitrogen and phosphorus,there are reasonable amount of these elements.

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0.50 mol A, 0.60 mol B, and 0.90 mol C are reacted according to the following reaction
algol [13]

Reactant C is the limiting reactant in this scenario.

Explanation:

The reactant in the balanced chemical reaction which gives the smaller amount or moles of product is the limiting reagent.

Balanced chemical reaction is:

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number of moles

A = 0.50 mole

B = 0.60 moles

C = 0.90 moles

Taking A as the reactant

1 mole of A reacted to form 2 moles of D

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thus 0.50 moles of A will produce 1 mole of D

Taking B as the reactant

2 moles of B reacted to form 2 moles of D

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x = 2 moles of D is produced.

Taking C as the reactant:

3 moles of C reacted to form 2 moles of D

O.9 moles of C reacted to form x moles of D

\frac{2}{3} = \frac{x}{0.9}

= 0.60 moles of D is formed.

Thus C is the limiting reagent in the given reaction as it produces smallest mass of product.

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