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masha68 [24]
3 years ago
8

Which of the following will receive electrical impulses next, after the structure indicated by the red arrow?

Physics
1 answer:
Savatey [412]3 years ago
8 0
Interventricular septum
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A girl is out jogging at 2.00 m/s and accelerates at 1.50 m/s^2 until she reaches a velocity of 5.00 m/s. How far does she get?
Maksim231197 [3]

Answer:

7.00 m

Explanation:

Given:

v₀ = 2.00 m/s

v = 5.00 m/s

a = 1.50 m/s²

Find: Δx

v² = v₀² + 2aΔx

(5.00 m/s)² = (2.00 m/s)² + 2(1.50 m/s²)Δx

Δx = 7.00 m

5 0
3 years ago
Scientific notation and graphing <br><br> 0.0004580 to scientific notation
Vlada [557]

Scientific Notation: 4.580 x 10^-4

Scientific e Notation: 4.580e-4

4 0
3 years ago
Read 2 more answers
If an object on a horizontal frictionless surface is attached to a spring, displaced, and then released, it oscillates. Suppose
o-na [289]

Answer:

a. Amplitude = 0.244 meters

b. Period = 1.62 seconds

c. Frequency = 0.6173 Hz

Explanation:

a.

With the position goes from 0.122 meters to -0.122 meters (negative because it is in the opposite side of the equilibrium point), the amplitude is the maximum value minus the minimum value:

Amplitude = 0.122 - (-0.122) = 0.122 + 0.122 = 0.244 meters

b.

The period is the amount of time the object takes to arrive in the same position again. So, if it takes 0.81 seconds to go to -0.122 m, it will take another 0.81 seconds to come back to 0.122 m, so the period is the sum of these two times:

Period = 0.81 + 0.81 + 1.62 seconds

c.

The frequency of the movement is the inverse of the period:

Frequency  = 1 / Period

So if the period is 1.62 seconds, the frequency is:

Frequency = 1 / 1.62 = 0.6173 Hertz

5 0
3 years ago
If your front lawn is 16.016.0 feet wide and 20.020.0 feet long, and each square foot of lawn accumulates 13501350 new snowflake
asambeis [7]

Answer:

The mass of snow accumulated in the lawn in 1 hour equals 57.024 kilograms

Explanation:

Given

Width of lawn = 16 feet

Length of lawn = 20 feet

Thus total area of lawn equals 16\times 20=320sq.feet\

Now it is given that 1 square foot accumulates 1350 new snowflakes each minute thus number of snowflakes accumulated by 320 square feet in 1 minute equals

320\times 1350=432000

Now it is given that average mass of each snowflake is 2.20mg=2.20\times 10^{-3}g=2.20\times 10^{-6}kg

Hence the mass accumulated per minute equals 432000\times 2.20\times 10^{-6}=0.9504kg

Now since there are 60 minutes in 1 hour thus the mass accumulated in 1 hour equals 0.9504kg\times 60=57.024kg

4 0
3 years ago
How much work is done when a hoist lifts a 210-kg rock to a height of 3 m? (Use 9.8 m/s2 for the acceleration due to gravity.)
Aleksandr [31]

Work done to lift the rock is 6174 Joule.

To find the answer, we need to know about the work done.

<h3>What's the work done?</h3>

Mathematically, work done = force × distance

<h3>What's the gravitational force acts on the stone here?</h3>

The gravitational force on the stone = mg

= 210× 9.8= 2058N

<h3>What's the work done to lift the stone?</h3>

Work done= 2058× 3

= 6174 Joule

Thus, we can conclude that the work done to lift the stone is 6174 Joule.

Learn more about the work done here:

brainly.com/question/25573309

#SPJ4

4 0
2 years ago
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