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3 years ago

Find the momentum of a 25kg object traveling at a speed of 4m/s

Physics

1 answer:

solong [7]3 years ago

8 0

Answer:

100Kg.m/s

Explanation:

From the question, we obtained the following information:

M= Mass = 25kg

V = Velocity = 4m/s

Momentum =?

Momentum = MV = 25x4= 100Kg.m/s

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A train travelling at 20m/s undergoes a uniform deceleration of 2m/s2 when brakes are applied.. calculate the time taken to come

VLD [36.1K]

Answer:

a) 10 seconds

b) 100 meters

Explanation:

<u>Accelerated Motion </u>

If an object is moving at contant speed, we know it has zero net force applied. As soon as an unbalanced force appears, the object accelerates (positive or negative) depending on the direction of the force with respect to movement. The speed of an object subject to acceleration is given by

$v_f=v_o+at$

The distance traveled is given by

$\displaystyle x=v_ot+\frac{at^2}{2}$

Our train is travelling at 20m/s when it decelerates at $-2\ m/s^2$ (negative for it's against movement). If nothing else happens, it will eventually stop ( $v_f=0$ ). We can compute the time at which it happens :

$\displaystyle t=\frac{v_f-v_o}{a}$

$Knowing\ v_f=0$

$\displaystyle t=\frac{-20}{-2}=10\ sec$

The distance traveled is

$\displaystyle x=v_ot+\frac{at^2}{2}$

$\displaystyle x=(20)(10)-\frac{2(10)^2}{2}$

$\displaystyle x=100\ m$

6 0

2 years ago

Two objects were lifted by a machine

bogdanovich [222]

And what finish the question

3 0

2 years ago

If a hockey player starts from rest and accelerates at a rate of 2.1 m/s², how long does it take him to skate 30 m?

Vlada [557]

Answer:

its A i think im not sure tho

Explanation:

5 0

3 years ago

When a driver presses the brake pedal, his car can stop with an acceleration of 5.4 m/s2. How far will the car travel while comi

notsponge [240]

$Given:\\a=5.4 \frac{m}{s^2} \\v_0= 25\frac{m}{s} \\\\Find:\\s=?\\\\Solution:\\\\s=v_0t- \frac{at^2}{2} \\\\a= \frac{\Delta v}{t} \\\\v_e=0\Rightarrow \Delta v=v_0\\\\t= \frac{v_0}{a} \\\\s= \frac{v_0^2}{a} - \frac{v_0^2}{2a} =\frac{v_0^2}{2a} \\\\s= \frac{ (25\frac{m}{s})2 }{2\cdot 5.4 \frac{m}{s^2} } \approx 57.9m\\\\C\rightarrow Correct\;answer$

3 0

3 years ago

A geneticist looks through a microscope to determine the phenotype of a fruit fly. The microscope is set to an overall magnifica

Ugo [173]

Answer:

$f_{e}$ = 1.9 cm

Explanation:

The magnification of a microscope is the product of the magnification of the eyepiece by the magnifier with the objective

M = M₀ $m_{e}$

Where M₀ is the magnification of the objective and $m_{e}$ is the magnification of the eyepiece.

The eyepiece is focused to the near vision point (d = 25 cm)

$m_{e}$ = 25 / $f_{e}$

The objective is focused on the distances of the tube (L)

M₀ = -L / f₀

Substituting

M = - L/f₀ 25/ $f_{e}$

1) Let's look for the focal length of the eyepiece (faith)

$f_{e}$ = - L 25 / f₀ M

M = 400X = -400

$f_{e}$ = - 12 25 /0.40 (-400)

$f_{e}$ = 1.875 cm

Let's approximate two significant figures

$f_{e}$ = 1.9 cm

8 0

3 years ago