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vitfil [10]
2 years ago
6

Research paper on tsunamis (4-5 paragraphs minimum) 3) Tsunamis how they work….evacuation routes, structures built in oceans to

protect, early detection, etc
Expectations:

A. Must be at least 4 full paragraphs. (probably will need to be more)

B. Must have an introductory paragraph that explains what the problem is, and the general overview of the paper.

C. Must Define Problem, including details and how it relates to Irvine

D. Main Body of Paper (probably couple of paragraphs) This is where you will show what you found out in your research. Make sure to include things like current use/techniques, as well as what technological advancements are being researched to improve your specific topic/issue.

E. Conclusion: Short summary of main points. Your Opinion on what is working and why (or what is not working and why)

F. Citations: Must use at LEAST 3 sources. Must site works at end, in either MLA or APA format, AND must site them where used in the paper (also MLA or APA format).

Make sure all work is yours and original. Copying is cheating. Using information from a source without citing is plagiarism.
Physics
1 answer:
elena55 [62]2 years ago
6 0
A must be at least 4 full paragraphs probably will need more
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A typical laboratory centrifuge rotates at 4000 rpm. Testtubes have to be placed into a centrifuge very carefully because ofthe
Bogdan [553]

Answer:

A)  a_c = 1.75 10⁴ m / s², B) a = 4.43 10³ m / s²

Explanation:

Part A) The relation of the test tube is centripetal

               a_c = v² / r

the angular and linear variables are related

              v = w r

we substitute

               a_c = w² r

let's reduce the magnitudes to the SI system

              w = 4000 rpm (2pi rad / 1 rev) (1 min / 60s) = 418.88 rad / s

               r = 1 cm (1 m / 100 cm) = 0.10 m

let's calculate

              a_c = 418.88² 0.1

               a_c = 1.75 10⁴ m / s²

part B) for this part let's use kinematics relations, let's start looking for the velocity just when we hit the floor

as part of rest the initial velocity is zero and on the floor the height is zero

                v² = v₀² - 2g (y- y₀)

                v² = 0 - 2 9.8 (0 + 1)

                v =√19.6

                v = -4.427 m / s

now let's look for the applied steel to stop the test tube

                v_f = v + a t

                0 = v + at

                a = -v / t

                a = 4.427 / 0.001

                a = 4.43 10³ m / s²

4 0
3 years ago
What main factor determines the stages a star will follow after the main sequence?.
Artyom0805 [142]

The main factor that determines the stages a star will follow after the main sequence is the star's mass or size.

<h3>What is main sequence?</h3>

The main sequence of a star is a stage in the life cycle of that star. During the main sequence ( also called the zero age ), the star generates energy by nuclear fusion of Hydrogen atoms at the core of the star into Helium atoms. Eventually, the star runs out of hydrogen atoms, which concludes the main sequence. What happens afterward depends on the size of the star.

<h3>Low mass stars </h3>

For low-mass stars ( stars that are less than 0.1 times the mass of the sun), they slowly collapse into white dwarfs. These stars do not get hot enough to fuse helium atoms, instead hydrogen fusion continues until the whole star is filled with helium and slowly collapses into a white dwarf while it grows dimmer and colder.

<h3>Medium-sized stars</h3>

Medium-sized stars ( stars about 0.6 - 10 times the mass of our sun) become red giants. Stars similar in size to our sun are hot enough to fuse helium atoms, so towards the end of the main sequence it starts to fuse helium atoms, forming heavier elements like carbon and oxygen. The heavier elements move to the star's core due to gravity, while lighter elements like hydrogen form a shell around the core. This causes the sun to then grow in size, forming a red giant.  

<h3>Large stars</h3>

Massive stars ( greater than 10 times the mass of the sun) and super-massive stars ( more than 40 times the mass of the sun ) end up exploding into a supernova , while the dense core collapses into a neutron star or a black hole.

To know more about main sequence, check out;  

brainly.com/question/18141359

#SPJ4

5 0
1 year ago
What defines minerals will mark brainlest if croccted right
zvonat [6]
<span> Uniform chemical composition
Solid
Crystalline structure </span>these are the characteristics of minerals
3 0
2 years ago
What can I do to increase range of motion in a joint
Phantasy [73]

Answer:

Damian here! (ノ◕ヮ◕)ノ*:・゚✧

Stretching is used to improve range-of-motion (ROM) of a joint, but why? The most common reason is that the joint ROM is limited and is somehow affecting performance of a desired activity. Stretching is also used as a preventative measure.

Explanation:hope this helps? :))

8 0
3 years ago
A positive charge of 18nC is evenly distributed along a straight rod of length 4.0 m that is bent into a circular arc with a rad
sergey [27]

Explanation:

Formula for angle subtended at the center of the circular arc is as follows.

           \theta = \frac{S}{r}

where,   S = length of the rod

              r = radius

Putting the given values into the above formula as follows.      

                \theta = \frac{S}{r}

                             = \frac{4}{2}

                             = 2 radians (\frac{180^{o}}{\pi})

                             = 114.64^{o}

Now, we will calculate the charge density as follows.

                 \lambda = \frac{Q}{L}

                            = \frac{18 \times 10^{-9} C}{4 m}

                            = 4.5 \times 10^{-9} C/m

Now, at the center of arc we will calculate the electric field as follows.

                 E = \frac{2k \lambda Sin (\frac{\theta}{2})}{r}

                     = \frac{2(9 \times 10^{9} Nm^{2}/C^{2})(4.5 \times 10^{-9}) Sin (\frac{114.64^{o}}{2})}{2 m}

                      = 34.08 N/C

Thus, we can conclude that the magnitude of the electric eld at the center of curvature of the arc is 34.08 N/C.

5 0
3 years ago
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