The micromoles of mercury(II) iodide : 0.013 μ moles
<h3>Further explanation</h3>
Given
215.0mL of a 6.0x10⁻⁵mmol/L HgI₂
Required
micromoles of HgI₂
Solution
Molarity(M) = moles of solute per liters of solution
Can be formulated :
M = n : V
n = moles
V = volume of solution
V = 215 mL = 0.215 L
so moles of solution :
n = M x V
n = 6.10 mmol/L x 0.215 L
n = 1.312 . 10⁻⁵ mmol
mmol = 10³ micromol
so 1.312 mmol = 1.312.10⁻⁵ x 10³ = 0.01312 micromoles ⇒ 2 sif fig = 0.013 μ moles
Ans: The entropy change for the given reaction is 93.3 J/K
Given reaction:
Br2(l) → Br2(g)
ΔS = ∑n(products)S⁰(products) - ∑n(reactants)S⁰(reactants)
= 1 mole* S°(Br2(g)) - 1 mole*S°(Br2(l))
= 1 mole *245.5 J/mol-K - 1 mole*152.2 J/mol-K
= 93.3 J/K
Answer: The first steps
Explanation: science
Answer:
63.1 seconds.
Explanation:
Hello!
In this case, since the average adult heart pumps 84.0 mL/s of blood, it means 84.0 mL each second, as we have 5300. mL, the following mathematical set up help us to compute the required time:
Which is about 1.05 min.
Best regards!
24g 4Al+3O2=2Al2O3
27g x(g)
108 96
X=24g
