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2 years ago

15

Compare and contrast the Andes Mountains and the Rocky Mountains. How are they formed? What consumers and producers are in each?

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1 answer:

Naily [24]2 years ago

7 0

Answer:

ummm i need help too lol

Explanation:

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Which of the following increases the average kinetic energy of colliding particles

Solnce55 [7]

I'm pretty sure the answer is Temperature

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3 years ago

What is the molar mass of CO2

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Molar mass of CO2 = 44.01 g/mol

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3 years ago

Sulfur is an element that can be seen on the periodic table. What will most likely occur if sulfur forms an ionic bond with anot

Yakvenalex [24]

What is likely to occur if sulfur forms an ionic bond with another element is <u>sulfur will accept electrons</u>

<u><em> explanation</em></u>

Ionic bond is formed when a metal react with a non metal.

Metal loses ( donate) electrons to form cation ( a positively charged ion) , while non metal accept (gain) electrons to form anion ( a negatively charged ion ).

Sulfur is a non metal therefore it accept electrons if it form an ionic bond with a metal. sulfur accept 2 electrons to form S2- ion

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2 years ago

Read 2 more answers

What are some examples of fusion

sveticcg [70]

Answer:

Example of a fusion dish: combination of smoked salmon wrapped in rice paper, with avocado, cucumber and crab sticks. Fusion cuisine is cuisine that combines elements of different culinary traditions that originate from different countries, regions, or cultures.

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2 years ago

Two unknown molecular compounds were being studied. A solution containing 5.00 g of compound A in 100. g of water froze at a low

LenaWriter [7]

Answer:

Compound B has greater molar mass.

Explanation:

The depression in freezing point is given by ;

$\Delta T_f=i\times k_f\times m$ ..[1]

$m=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Mass of solvent in kg}}$

Where:

i = van't Hoff factor

$k_f$ = Molal depression constant

m = molality of the solution

According to question , solution with 5.00 g of A in 100.0 grams of water froze at at lower temperature than solution with 5.00 g of B in 100.0 grams of water.

The depression in freezing point of solution with A solute: $\Delta T_{f,A}$

Molar mass of A = $M_A$

The depression in freezing point of solution with B solute: $\Delta T_{f,B}$

Molar mass of B = $M_B$

$\Delta T_{f,A}>\Delta T_{f,B}$

As we can see in [1] , that depression in freezing point is inversely related to molar mass of the solute.

$\Delta T_f\propto \frac{1}{\text{Molar mass of solute}}$

$M_A$

This means compound B has greater molar mass than compound A,

4 0

3 years ago