Answer:
average shear strain in the rubber is 0.25rad
Explanation:
The base has a dimension of 20mm and 50mm.
frictional force is 50 N
using the expressed shear stress,
we will determine τ =
τ = 50 / 1000
= 0.05MPa
shear stress τ = γ .G
τ = shear stress
γ = shear strain
G = 0.20MPa
γ = τ / G
= 0.05 / 0.20
= 0.25rad
average shear strain in the rubber is 0.25rad
Answer:
So the sound intensity level they would experience without the earplugs is 110.32dB.
Explanation:
Given data
Sound intensity by factor =215
Sound intensity level =87 dB
To find
Sound intensity level they would experience without the earplugs
Solution
First we need to find the new sound intensity level
So
The dB can be calculated as:
Substitute the given values
So the sound intensity level they would experience without the earplugs is 110.32dB.
Answer:
Frequency is
Explanation:
Distance between source 1 from the receiver ,
Distance between source 2 from the receiver ,
Now ,
Path difference ,
We know, for constructive interference path difference should be integral multiple of wavelength .
Therefore,
It is given that n = 1,
Therefore,
Frequency can be found by ,
Hence, this is the required solution.