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Over [174]
3 years ago
5

Which describes who will record their measurements in joules?

Physics
2 answers:
enot [183]3 years ago
5 0

Answer:

Lily, Astrid, Henry, and Bob

Explanation:

Aleksandr [31]3 years ago
3 0

Answer: Lily, Astrid, Henry, and Bob

Explanation:

By a small online search i've found the image related to this question, and you can see it below.

Joules is a unit of energy, such that:

Joule = kg*m^2/s^2

In other hand, Watt is a unit of power, such that:

1 W = 1 J/s

Then if we measure power, we are measuring watts, which is equivalent to measuring the total amount of energy in joules in a given period of time, and then dividing that by the time. And if we measure energy, we are directly measuring joules.

Then if we measure power or energy, at some point our measures will be in joules (unless we have an specific device to measure power, but these usually exist for electronic systems, not for mechanical/dinamic systems like the ones in the image), this means that all of them will record their measurements in joules, so the correct option is Lily, Astrid, Henry, and Bob

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In order to measure the size of the electrical current flowing in the circuit,
the current must pass through the meter.
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3 years ago
Which of the following is a subatomic particle?
mr Goodwill [35]

Answer:

neutron.

Explanation:

subatomic particles include,

neutron.

proton.

electron.

hope it helps. :)

4 0
2 years ago
Which of the following is an example of Newton's Third Law?* O A stack of pennies will not move unless you flick them over. O Fa
Morgarella [4.7K]

Answer:

A ball hits the ground and the ground pushes up on it

Explanation:

Newton's third law basically states that for every action, there's a reaction.

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Hope this Helps!!! :)

5 0
3 years ago
A Roller Derby Exhibition recently came to town. They packed the gym for two
arlik [135]

Answer:

14.36m/s

Explanation:

From the law of conservation of linear momentum

m1u1 + m2u2 = v(m1 + m2)

68×17 + 76×12= v(68+76)

1156+912 = 144v

2068 = 144v

v = 2068/144

=14.36 m/s

7 0
3 years ago
two engines are turned on for 763 s at a moment when the velocity of the craft has x and y components of v0x = 6380 m/s and v0y
svet-max [94.6K]

Answer:

Explanation:

Given

initial velocity component of engines is

v_0_x=6380 m/s

v_0_y=6770 m/s

time period of engine running=763 s

Displacement in x=4.50\times 10^6

y=7.27\times 10^6

Using s=ut+\frac{at^2}{2} in x and y direction

x=v_0_x\times t+\frac{at^2}{2}

4.50\times 10^6=6380\times 763+\frac{a\times 763^2}{2}

4.50\times 10^6-4.86\times 10^6=\frac{a\times 763^2}{2}

a=-1.23 m/s^2

In y direction

y=v_0_y\times t+\frac{a't^2}{2}

7.27\times 10^6=6770\times 763+\frac{a\times 763^2}{2}

7.27\times 10^6-5.16\times 10^6=\frac{a\times 763^2}{2}

a=7.24 m/s^2

x component=-1.23 m/s^2

y component=7.24 m/s^2

3 0
2 years ago
Read 2 more answers
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