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Over [174]
3 years ago
5

Which describes who will record their measurements in joules?

Physics
2 answers:
enot [183]3 years ago
5 0

Answer:

Lily, Astrid, Henry, and Bob

Explanation:

Aleksandr [31]3 years ago
3 0

Answer: Lily, Astrid, Henry, and Bob

Explanation:

By a small online search i've found the image related to this question, and you can see it below.

Joules is a unit of energy, such that:

Joule = kg*m^2/s^2

In other hand, Watt is a unit of power, such that:

1 W = 1 J/s

Then if we measure power, we are measuring watts, which is equivalent to measuring the total amount of energy in joules in a given period of time, and then dividing that by the time. And if we measure energy, we are directly measuring joules.

Then if we measure power or energy, at some point our measures will be in joules (unless we have an specific device to measure power, but these usually exist for electronic systems, not for mechanical/dinamic systems like the ones in the image), this means that all of them will record their measurements in joules, so the correct option is Lily, Astrid, Henry, and Bob

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In a wire, when elongation is 4 cm energy stored is E. if it is stretched by 4 cm, then what amount of elastic potential energy
myrzilka [38]
<h2>Answer:</h2>

4E

<h2>Explanation:</h2>

The elastic potential energy of an elastic material (e.g a spring, a wire), is the energy stored when the material is stretched or compressed. It is given by

U = \frac{1}{2}kx^2               --------------------(i)

Where;

U = potential energy stored

k = spring constant of the material

x = elongation (extension or compression of the material).

<em>From the first statement;</em>

<em>when elongation (x) is 4cm, energy stored (U) is E</em>

<em>Substitute these values into equation (i) as follows;</em>

E = \frac{1}{2}k(4)^2

E = 8k

<em>Make k subject of the formula</em>    

k = \frac{E}{8}   [measured in J/cm]

<em>From the second statement;</em>

<em>It is stretched by 4cm.</em>

This means that total elongation will be 4cm + 4cm = 8cm.

The potential energy stored will be found by substituting the value of x = 8cm and k = \frac{E}{8} into equation (i) as follows;

U = \frac{1}{2}\frac{E}{8} (8)^2  

U = \frac{1}{2}{8E}

U = {4E}

Therefore, the potential energy stored will now be 4 times the original one.

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3 years ago
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