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Dovator [93]
3 years ago
5

Increasing which of the following would increase the magnetic force between the permanent magnet and the coil? A. Transformer B.

Circuit C. Current D. Generator
Physics
1 answer:
Gnoma [55]3 years ago
7 0

For this one, all you really need to do is eliminate any answers
that are absurd or meaningless.

You can't increase a transformer.
You can't increase a circuit.
You can't increase a generator.

When the <em><u>current</u></em> through a coil of wire increases, the magnetic field
around the coil increases, so there would be more magnetic force
between the coil and a permanent magnet.


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A uniform string of length 10.0 m and weight 0.32 N is attached to the ceiling. A weight of 1.00 kN hangs from its lower end. Th
Juliette [100K]

Answer: 0.0180701 s

Explanation:

Given the following :

Length of string (L) = 10 m

Weight of string (W) = 0.32 N

Weight attached to lower end = 1kN = 1×10^3

Using the relation:

Time (t) = √ (weight of string * Length) / weight attached to lower end * acceleration due to gravity

g = acceleration due to gravity = 9.8m/s^2

Weight of string = 0.32N

Time(t) = √ (0.32 * 10) / [(1*10^3) * (9.8)]

Time = √3.2 / 9800

= √0.0003265

= 0.0180701s

5 0
3 years ago
If you pour different liquids into a graduated cylinder, which layer would be at the bottom?
klasskru [66]

the one that is more dense!

5 0
3 years ago
A go-cart and rider have a mass of 14 kg. If the cart accelerates at 6m/s^2 during a 40 m sprint in 100 seconds, how much power
lara [203]

Answer:

P = 33.6 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces [N]

m = mass = 14 [kg]

a = acceleration = 6 [m/s²]

F = 14*6\\F = 84 [N]

In the second part of this problem we must find the work done, where the work in physics is known as the product of force by distance, it is important to make it clear that force must be applied in the direction of movement.

W = F*d

where:

W = work [J]

F = force = 84 [N]

d = displaciment = 40 [m]

W = 84*40\\W = 3360 [J]

Finally, the power can be calculated by the relationship between the work performed in a given time interval.

P=W/t\\

where:

P = power [W]

W = work = 3360 [J]

t = time = 100 [s]

Now replacing:

P=3360/100\\P=33.6[W]

The power is given in watts

3 0
2 years ago
A paper airplane with mass 0.1 kg is flying 1.5 m above the ground with a speed of 2 m/s. What is the total mechanical energy of
Wewaii [24]
Total mechanical energy = kinetic energy + potential energy
E = KE + PE
E = ½mv² + mgh
E = ½(0.1 kg)(2 m/s)² + (0.1 kg)(9.8 m/s²)(1.5 m)
E = 0.2 J + 1.47 J
E = 1.67 J
7 0
3 years ago
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Which statement best describes perigee?
Margarita [4]
A. is meaningless.
B. is perigee.
C. is apogee.
D. is perihelion.
5 0
3 years ago
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