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2 years ago

Noelle recieves $17,000 in two loans. One loan charges

Mathematics

1 answer:

Travka [436]2 years ago

6 0

Answer:

5% interest loan is $9000;

6.5% interest loan is $8000.

Step-by-step explanation:

1.We assume 5% loan is x and 6.5% loan is y.

2.Two loan is total is $17000

So we can say: x+y = 17000

3.Each loans have its own interest

5% loan will be 0.05 * x

6.5% loan will be 0.065 * y

Both is 0.05x+0.065y = 970

(eg: 5% = 0.05, 6.5% = 0.065)

4.So we get:

x+y=17000

0.05x+0.065y=970

solve it will get x= 9000, y = 8000.

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Let victor's savings = x

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This is all I need because its 55% of my grade on this practice, please help ty.

Dvinal [7]

Answer:

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Step-by-step explanation:

First question:

He starts with 18, gains 2 every week, and needs 42. This means the equation is $18+2x=42$ .

Second question:

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Third question:

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Fourth question:

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2 years ago

Tyrone has $500 in his savings account. He wants to save more money. He is looking at two investment plans. Under plan A, he wil

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Answer:

$\$522.78$

Step-by-step explanation:

Let

x ---> the number of years

y ---> the amount in the account balance

Plan A

we have a linear equation of the form

$y=mx+b$

where

The slope is equal to

$m=\$100\ per\ year$

The y-intercept or initial value is

$b=\$500$

substitute

$y=100x+500$

For x=10 years

substitute

$y=100(10)+500=\$1,500$

Plan B

we have a exponential growth function of the form

$y=a(1+r)^x$

where

$a=\$500\\r=15\%=15/100=0.15$

substitute

$y=500(1+0.15)^x$

$y=500(1.15)^x$

For x=10 years

substitute

$y=500(1.15)^{10}=\$2,022.78$

Find the difference of the two account balances after 10 years

$\$2,022.78-\$1,500=\$522.78$

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2 years ago

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Answer:

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