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dolphi86 [110]
3 years ago
7

If an atom had a nucleus 1 ft in diameter, what would be the diameter of the atom, in miles? (1 mi = 5,280 ft)

Physics
1 answer:
hjlf3 years ago
5 0
In nomine patris, et filii, et spiritus sancti. 
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If you are pushing a box toward your friend with a force of 20 N, and your friend is pushing the box toward you with a force of
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Answer : the box will move backwards with a force 10 N

Explanation :

F1 = 20 N

F2 = 30 N

F = F2 - F1 = 30 - 20 = 10 N

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True or False: An acid is a solution that has an excess of H+ ions.
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true

Explanation:

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How to play track and field
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Explanation:

Track and Field is a sport, which is includes disciplines of running, jumping, and throwing events. The sport traces back to Ancient Greece. The first recorded examples of this sport were at the Ancient Greek Olympics. In Ancient Greece, only one event was contested, the stadion footrace. Later on, the game expanded to more events.Events of track and field are divided into three: track events, field events, and combined events. Track events consist of Sprints, middle-distance, long distance, hurdles and relays; Field events consist of jumps and throws; while combined events consist of pentathlon, heptathlon, and decathlon. Track and field is usually played outdoors in stadiums. The usual features of a track and field stadium are the outer running track, and the field within the track

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When you hear a noise, you usually know the direction from which it came even if you cannot see the source. This ability is part
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Near the top of the Citigroup Center building in New York City, there is an object with mass of 4.8 x 105 kg on springs that hav
Vikki [24]

Answer:

The force constant is  k =1.316 *10^{7} \  N/m

The energy stored in the spring is  E =  1.68 *10^{7} \ J

Explanation:

From the question we are told that

   The mass of the object is  M  = 4.8*10^{5} \ kg

    The period is T  = 1.2 \ s

The period of the spring oscillation is  mathematically represented as

         T  =2 \pi \sqrt{ \frac{M}{k}}

where  k is the force constant

   So making k the subject

       k = \frac{4 \pi ^2 M }{T^2}

substituting values

       k = \frac{4 (3.142) ^2 (4.8 *10^{5}) }{(1.2)^2}

      k =1.316 *10^{7} \  N/m

The energy stored in the spring is mathematically represented  as

       E =  \frac{1}{2} k x^2

Where x is the spring displacement which is given as

        x =  1.6 \ m

substituting values

      E =  \frac{1}{2} (1.316 *10^{7}) (1.6)^2

       E =  1.68 *10^{7} \ J

   

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