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Jlenok [28]
4 years ago
13

Question 5. Our results support the idea that if left to freely oscillate, a system will vibrate at a natural frequency that dep

ends on the system itself, not on the initial push or stimulus that we impart. Based on this reasoning, consider a beam made out of iron and an otherwise identical beam made out of aluminum. How should the natural frequency of vibration of these two beams compare

Physics
1 answer:
Gekata [30.6K]4 years ago
3 0

Answer:

(b) In ideal condition we neglect mass of spring but in real springs mass of spring adds another factor to its time period.

since we are adding a factor of mass to the system, and frequency being inversely proportional to squared root of mass, we can come to a general conclusion that it effectively reduces the natural frequency .

Explanation:

kindly check the attachment for explanation.

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If the torque on an object adds up to zero Group of answer choices the object is at rest. the object cannot be turning. the obje
garik1379 [7]

Answer:

the body has linear acceleration, but cannot rotate

Explanation:

Let's analyze the system

If the torque is zero, the two forces are the same magnitude, but applied to each side of the body in such a way that the torque cancels the punch of the other. Therefore the body cannot turn

The two forces go in the same direction so the object can have linear acceleration

The object is at rest because it has a force in the same direction, but in the opposite direction.

therefore the correct answer is:

the body has linear acceleration, but cannot rotate

8 0
3 years ago
Quasar spectra often show many absorption lines that all appear to be as a result of the same electron transition (such as level
Elanso [62]

Answer: Because of different redshift of cloud.

Explanation:

We are seeing absorption lines from clouds of gas that lie between us and the quasar, and therefore each cloud has a different redshift.

A quasar's spectrum is hugely redshifted. And most astronomers think this large redshift tells us about the distance to the quasar.

5 0
3 years ago
4. Some early mornings , dew drops can be found on grass or a car parked outside,
horsena [70]

In some early mornings , dew drops can be found on grass or a car parked outside, but not on other materials such as the sidewalk because  the night -time temperature on grass and the car went below the dew point, but  the temperature of the concrete did not drop enough to reach the dew point  level

Dew can be formed on any object when the temperature of the object drop. When this happen, the object will be cool which will eventually cool the surrounding air around the object.

Dew drops is as a result of condensation in the air. When the cool air causes the air vapor to convert to liquid. The dew will form when the temperature of the object balances with the dew point in the surrounding environment.

In some early mornings , dew drops can be found on grass or a car parked outside, but not on other materials such as the sidewalk because  the night -time temperature on grass and the car went below the dew point, but  the temperature of the concrete did not drop enough to reach the dew point  level

Therefore the correct option is therefore A

Learn more here : brainly.com/question/13834972

3 0
3 years ago
What s physics?
Alex777 [14]

The answer is (B. The study of Matter and Energy) but technically you could consider physics all of these as engineering is based on physics and that would be the study of inventions, chemistry and biology were both discovered because of physics, and physics invokes more math than any other subject as it applies math to the entire Universe.

7 0
4 years ago
Read 2 more answers
What is the wavelength of the third harmonic in a 4.5-m-long pipe that is closed at one end?
lisov135 [29]

Answer:

Wavelength of sound in the pipe is 6.0 m

Explanation:

As we know that closed pipe is given to us so here at open end it will form antinode while at closed end it will form Node

Here we know that in closed pipes on odd harmonics will exist

so here for third harmonic we have

L = \frac{\lambda}{4} + \frac{\lambda}{2}

where L = length of the pipe

so we have

4.5 = \frac{3\lambda}{4}

\lambda = 6.0 m

5 0
3 years ago
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