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lapo4ka [179]
3 years ago
8

If (-3)^-5 =1/x, what is the value of x?

Mathematics
1 answer:
iragen [17]3 years ago
7 0
\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}\\\\
-------------------------------\\\\
%(-3)^-5 =1/x,
(-3)^{-5}=\cfrac{1}{x}\implies \cfrac{1}{(-3)^5}=\cfrac{1}{x}\implies 1\cdot x=(-3)^5\cdot 1\implies x=(-3)^5
\\\\\\
x=(-3)(-3)(-3)(-3)(-3)\implies x=-243
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in the figure below trianglePQM and triangleQRP are right triangles. the measure of lineQM is 6 and the measure of lineQP is 8.
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Answer:

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Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

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Pythagoras formula

hypotenuse^2=base^2+perpendicular^2

Use pythagoras formula for triangle PQM.

PM^2=QM^2+PQ^2

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The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

PQ^2=QR^2+PR^2

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Use pythagoras formula for triangle MQR.

MQ^2=QR^2+MR^2

(6)^2=QR^2+(10-x)^2

36=QR^2+x^2-20x+100

36-x^2+20x-100=QR^2        .... (2)

From equation (1) and (2) we get

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20x-64=64

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3 0
3 years ago
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Answer:

answer is 1/8

Step-by-step explanation:

hope this helps

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3 years ago
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