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3 years ago

Find you equation of the line shown

Mathematics

2 answers:

VashaNatasha [74]3 years ago

5 0

Answer:

y=x+6

Step-by-step explanation:

(0,6). y=mx+b or 6=1 × 0+b, or solving for b: b=6-(1)(0). b=6.

(1,7). y=mx+b or 7=1 × 1+b, or solving for b: b=7-(1)(1). b=6.

I inputted two points from the graph and solved them.

Hence the equation would be y=x+6

Olenka [21]3 years ago

4 0

Answer:

y= x + 6

Step-by-step explanation:

For here we are looking for y= mx +b.

For the slope, It is y= 4/4.

That can be simplified into 1x or x.

Then look at where it contacts the y axis. It is at six. Plug all that in to get

y= x + 6

hope this helps!!

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Intravenous fluid bags are filled by an automated filling machine. Assume that the fill volumes of the bags are independent, nor

iren2701 [21]

Answer:

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,0.08)$

Where $\mu$ and $\sigma=0.08$

Since the distribution for X is normal then the we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error is given by:

$SE= \frac{0.08}{\sqrt{24}}= 0.0163$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,0.08)$

Where $\mu$ and $\sigma=0.08$

Since the distribution for X is normal then the we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error is given by:

$SE= \frac{0.08}{\sqrt{24}}= 0.0163$

8 0

3 years ago

If 150 empty water bottles weigh 4.5 pounds what do you expect 90 water empty bottles to weigh?

MakcuM [25]

It's 2.7 pounds because I set up a proportion of 150 over 90 = 4.5 over X and multiplied 90 * 4.5 divided by 150

6 0

3 years ago

Read 2 more answers

What is the inverse of the function f(x) = 4x + 8

Y_Kistochka [10]

Answer:

let f(x)= y

y = 4x+8

x= 4y + 8

4y = x - 8

y = (x - 8)/4

Hope this helps.

7 0

3 years ago

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two hundred tickets for the school play were sold. tickets cost $2 for students and $3 for adults. the total amount collected wa

Gre4nikov [31]

A system of equations is good for a problem like this.
Let x be the number of student tickets sold
Let y be the number of adult tickets sold
x + y = 200
2x + 3y = 490
x = 200 - y
2(200 - y) + 3y = 490
400 - 2y + 3y = 490
400 + y = 490
y = 90
The number of adult tickets sold was 90.
x + 90 = 200 --> x = 110
2x + 3(90) = 490 --> 2x + 270 = 490 --> 2x = 220 --> x = 110
The number student tickets sold was 110.

4 0

3 years ago

Which table represents a quadratic relationship?

svp [43]

In each case, the x-values are equally-spaced. Thus looking at second differences will tell you if the relation is quadratic. If the second differences are non-zero and constant, then the values have a quadratic relationship.

A. First differences are 2-4 = -2, 1-2 = -1, 0.5-1 = -0.5. Second differences are -1-(-2) = 1, -0.5-(-1) = 0.5. Since 1 ≠ 0.5, this relation is not quadratic. (It is exponential with a base of 1/2.)

B. First differences are 128-135 = -7, 105-128 = -23, 72-105 = -33. Second differences are -23-(-7) = -16, -33-(-23)=-10. Since -16 ≠ -10, this relation is not quadratic. (It is cubic, since 3rd differences are constant at +4.)

C. First differences are -23.2-(-23.4) = 0.2, -23.0-(-23.2) = 0.2, -22.8-(-23.0) = 0.2. Second differences are zero, so this is not a quadratic relation. (It is linear, with a slope of 0.2.)

D. First differences are 56-90 = -34, 26-56 = -30, 0-26 = -26. Second differences are -30-(-34) = 4, -26-(-30) = 4. These are constant (=4), so the relation is quadratic.

The appropriate choice is ...

... D. x -1 0 1 2 3 4

... f(x) 90 56 26 0 -22 -40

4 0

4 years ago

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