Divide 5/8 by 150, to see how thick each is, that'll give you 150 even pieces that add up to 5/8
The equation of a hyperbola is:
(x – h)^2 / a^2 - (y – k)^2 / b^2 = 1
So what we have to do is to look for the values of the variables:
<span>For the given hyperbola : center (h, k) = (0, 0)
a = 3(distance from center to vertices)
a^2 = 9</span>
<span>
c = 7 (distance from center to vertices; given from the foci)
c^2 = 49</span>
<span>By the hypotenuse formula:
c^2 = a^2 + b^2
b^2 = c^2 - a^2 </span>
<span>b^2 = 49 – 9</span>
<span>b^2 = 40
</span>
Therefore the equation of the hyperbola is:
<span>(x^2 / 9) – (y^2 / 40) = 1</span>
The range is 13 because 115-102 is 13
240 ft^2 = L X W
240 = 3W x W
240 = 3W^2
W = 8.94427 ft
L = 3W = 3(8.94427)
L = 26.8328 FT
