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4 years ago

Discuss why temperature is the most important factor in determining the state of a substance

Chemistry

1 answer:

Roman55 [17]4 years ago

8 0

Its important because the temp can either take away or add energy to a substance.

hope this helps

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10. (2 points) What is the process by which a solute forms a solution in a solvent. A) calisthenics B) bumping C) dissolution D)

Triss [41]

Answer: (C) Dissolution is the process by which a solute form a solution in a solvent.

Explanation: Dissolution can be described as the process by which a solute dissolves in a solvent to give a solvent.

The solute may be a solid, liquid or gas and solvent is usually a liquid but can also be liquid, gas or supercritical fluid. The most common solvent is water and it is referred to as the universal solvent.

Example are:

1.Stirring of sugar in water.

In this case the solute is the sugar and the solvent is water.

2.Organic substances dissolves readily in solvent like kerosene and benzene and they are known as non-polar solvent while the organic substances are the solute

4 0

3 years ago

Every conversion factor is a ratio that is<br> equal to 1<br> less than 1<br> greater than 1

miss Akunina [59]

equal to 1

Explanation:

All conversion factors used in any calculation is usually a ratio that is equal to 1. This is because when 1 is used to multiply or divide any number, the number stays the same.

Conversion factors are useful in making the simplification of an expression very simple. They are usually ratios of 1.
It follows that a conversion factor is a number that when multiplied or divided by itself will stay the same.

Learn more:

conversion factor: brainly.com/question/555814

#learnwithBrainly

4 0

4 years ago

Describe two ways in which sodium chloride is different from sodium

KATRIN_1 [288]

Answer:

sodium chloride is a component is a salt made of a metal Sodium and a non chlorine is a alone only and element and very less stable until bonded with them metal like a n, a, k or H

7 0

3 years ago

There are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with

grandymaker [24]

$\text{Hg} \text{O}$ and $\text{Hg}_{2} \text{O}$ .

Assuming complete decomposition of both samples,

$m(\text{Hg}) = m(\text{residure})$
$m(\text{O}) = m(\text{loss})$

First compound:

$m(\text{O}) = m(\text{loss}) = 0.6498 - 0.6018 = 0.048 \; g$
$m(\text{Hg}) = m(\text{residure}) = 0.6018 \; g$

$n = m/M$ ; $0.6498 \; g$ of the first compound would contain

$n(\text{O atoms}) = 0.048 \; g / 16 \; g \cdot mol^{-1}= 0.003 \; mol$
$n(\text{Hg atoms}) = 0.6018 \; g / 200.58 \; g \cdot mol^{-1}= 0.003 \; mol$

Oxygen and mercury atoms seemingly exist in the first compound at a $1:1$ ratio; thus the empirical formula for this compound would be $\text{Hg} \text{O}$ where the subscript "1" is omitted.

Similarly, for the second compound

$m(\text{O}) = m(\text{loss}) = 0.016 \; g$
$m(\text{Hg}) = m(\text{residure}) = 0.4172 - 0.016 = 0.4012 \; g$

$n = m/M$ ; $0.4172 \; g$ of the first compound would contain

$n(\text{O atoms}) = 0.016 \; g / 16 \; g \cdot mol^{-1}= 0.001 \; mol$
$n(\text{Hg atoms}) = 0.4012 \; g / 200.58 \; g \cdot mol^{-1}= 0.002 \; mol$

$n(\text{Hg}) : n(\text{O}) \approx 2:1$ and therefore the empirical formula

$\text{Hg}_{2} \text{O}$ .

8 0

3 years ago

If 7.0 mol sample of a gas has a volume of 12.2 L, what would the volume be if the amount of gas was increased to 16.8 mol

Leviafan [203]

Answer:

$V_{2} = 29.28\,L$

Explanation:

Let assume that gas behaves ideally and experiments an isobaric and isothermal processes. The following relationship is applied to determined the final volume:

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$

$V_{2} = V_{1} \cdot \left(\frac{n_{2}}{n_{1}} \right)$

$V_{2} = (12.2\,L)\cdot \left(\frac{16.8\,moles}{7\,moles} \right)$

$V_{2} = 29.28\,L$

5 0

3 years ago