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3 years ago

If an atom has 17 protons, 15 neutrons, and 20 electrons, what is the atom's electrical charge?

1 answer:

3 0

The overall charge on this ion is -3. Neutrons don’t carry a charge, while protons and electrons carry a net +1 and -1 charge, respectively. In this case, the electrons outweigh the protons by 3, making the overall charge -3.

Hope this helps!

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What mass of silver can be plated onto an object in 33. 5 minutes at 8. 70 a of current? ag (aq) e- → ag(s) 19. 6 g 9. 78 g 0. 3

grandymaker [24]

Mass of silver can be plated onto an object in 33. 5 minutes at 8. 70 a of current is 19.55 g

Given, I=8.70A, t=33.5min=33.5*60=2010 sec, m of Ag = 19600g M=107.87 g/mol

From faradays law we can write q=I*t= 8.70*2010=17487 C.

moles of Ag =17487/ 19600=0.1812 moles

Ag deposited = 0.1812*107.87 = 19.55 g

<h3>Silver </h3>

Having the atomic number 47 and the Latin word argentum, which means "bright" or "white," silver is a chemical element. Its symbol is Ag. The highest electrical, thermal, and reflectivity of any metal are displayed by this transition metal, which is soft, white, and lustrous. The metal can be found in the Earth's crust in three different forms: as an alloy with other metals like gold and in minerals like argentite and chlorargyrite. It can also be found in its pure, free elemental form, also known as "native silver." During the refining of copper, gold, lead, and zinc, the majority of silver is created as a byproduct. As a valuable metal, silver has long been treasured.

What mass of silver can be plated onto an object in 33. 5 minutes at 8. 70 a of current? ag (aq) e- → ag(s) 19. 6 g 9. 78 g 0. 326 g 3. 07 g 0. 102 g

Learn more about Silver here:

brainly.com/question/14587716

#SPJ4

4 0

2 years ago

Mrs. DeFord wanted to know whether or not her students would do better on a quiz if she promised them candy.

marta [7]

Answer:

a.) Independent Variable: # of candy bars promised to each group

[ The Independent Varaiable is what you change in the experiment]

b.) Dependent Variable: Quiz Scores

[ The Dependent Variable is what you're testing in the experiment; what the experiment should affect]

c.) Constant(s): Same Quiz, same number of gender kids in each group, same age kids in each group, same ability, and same background. [and same time, I'm assuming.]

[Constants are what you keep the same in the experiment; what you're not changing.]

d.) Testable Question: Will promising kids candy make them do better on tests and quizzes? [or something along this lines of this]

[The Testable Question is what you're trying to find out in the experiment]

e.) Hypothesis: The more candy the students were promised, the better results Mrs. DeFord would get from them.

[The Hypothesis is what the person performing the experiment expects will happen; an educated guess]

f. Formal Conclusion: Data shows that kids who were promised more candy had a better average than kids who were promised less candy/none. Mrs. DeFord's hypothesis was correct, since she assumed the more candy the students were promised, the better they would do on the quiz.

[The Formal Conclusion is what you have learned from the experiment, and wether or not the hypothesis was correct or not.]

I hope this helps! :)

6 0

4 years ago

Read 2 more answers

2. What mass of water absorbs 6700 J of heat to raise the temperature from 283K to 318K?

Alexxandr [17]

Answer:

Q = mcT ...you can either substitute the molar heat capacity of water in the place of c or the specific heat capacity of water.

Explanation:

7 0

3 years ago

CHEM HELP ASAP!! <br><br> What mass of H2 would be needed to produce 208 kg of methanol?

Eddi Din [679]

So if we use the equation:

$CO+2H_{2}$ → $CH_{3}OH$

We can then determine the amount of $H_{2}$ needed to produce 208 kg of methanol.

So let's find out how many moles of methanol 208 kg is:

Methanol molar weight = 32.041g/mol

So then we can solve for moles of methanol:

$208kg*\frac{1,000g}{1kg} *\frac{1mol}{32.041g} =6,491.68mol$

So now that we have the amount of moles produced, we can use the molar ratio (from the balanced equation) of hydrogen and methanol. This ratio is 2:1 hydrogen:methanol.

Therefore, we can set up a proportion to solve for the moles of hydrogen needed:

$\frac{2}{1} =\frac{x}{6,491.68}$

$x=12,983.36mol$

So now that we have the number of moles of $H_{2}$ that are produced, we can then use the molar weight of hydrogen to solve for the mass that is needed:

$12,983.36mol*\frac{2.016g}{1mol} =26,174.45g_H_{2}$

Therefore, the amount of diatomic hydrogen ( $H_{2}$ ) that is needed to produce 208kg of methanol is $2.62x10^{4}$ g.

3 0

3 years ago

Which group of organisms disappeared during the mass extinction at the end of the Cretaceous Period?

jolli1 [7]

Answer:

saber tooth cats

Explanation:

7 0

3 years ago